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Ch. R - Algebra Review
Lial - Trigonometry 12th Edition
Lial12th EditionTrigonometryISBN: 9780136552161Not the one you use?Change textbook
Chapter 1, Problem R.6.55

Solve each quadratic equation using the square root property. See Example 6. x² - 27 = 0

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Start with the given quadratic equation: \(x^{2} - 27 = 0\).
Isolate the squared term by adding 27 to both sides: \(x^{2} = 27\).
Apply the square root property, which states that if \(x^{2} = a\), then \(x = \pm \sqrt{a}\).
Take the square root of both sides: \(x = \pm \sqrt{27}\).
Simplify the square root if possible by factoring out perfect squares: \(\sqrt{27} = \sqrt{9 \times 3} = 3\sqrt{3}\), so \(x = \pm 3\sqrt{3}\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Square Root Property

The square root property states that if x² = k, then x = ±√k. This method is used to solve quadratic equations that can be written in the form x² = constant by isolating x² and then taking the square root of both sides, considering both positive and negative roots.
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Isolating the Variable Term

Before applying the square root property, the quadratic equation must be rearranged so that the x² term is isolated on one side of the equation. This often involves adding or subtracting constants to both sides to simplify the equation into the form x² = number.
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Handling Negative Values Under the Square Root

If the constant on the right side of the equation is negative, the solution involves imaginary numbers because the square root of a negative number is not real. In such cases, the solutions are expressed using the imaginary unit i, where i² = -1.
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