Ch. 2 - Graphs of the Trigonometric Functions; Inverse Trigonometric Functions

Blitzer3rd EditionTrigonometryISBN: 9780137316601Not the one you use?Change textbook

Blitzer 3rd Edition

Ch. 2 - Graphs of the Trigonometric Functions; Inverse Trigonometric Functions

Problem 45

Chapter 2, Problem 45

In Exercises 29–51, find the exact value of each expression. Do not use a calculator. sin(cos⁻¹ 3/5)

Verified step by step guidance

Recognize that the expression is \( \sin(\cos^{-1}(\frac{3}{5})) \). Here, \( \cos^{-1}(\frac{3}{5}) \) represents an angle \( \theta \) such that \( \cos(\theta) = \frac{3}{5} \).

Visualize or draw a right triangle where the adjacent side to angle \( \theta \) is 3 and the hypotenuse is 5, based on the cosine ratio \( \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \).

Use the Pythagorean theorem to find the length of the opposite side: \( \text{opposite} = \sqrt{5^2 - 3^2} = \sqrt{25 - 9} \).

Simplify the expression under the square root to find the opposite side length: \( \sqrt{16} \).

Calculate \( \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{\sqrt{16}}{5} \), which gives the exact value of \( \sin(\cos^{-1}(\frac{3}{5})) \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Inverse Trigonometric Functions

Inverse trigonometric functions, like cos⁻¹(x), return the angle whose trigonometric ratio equals x. For example, cos⁻¹(3/5) gives the angle θ such that cos(θ) = 3/5. Understanding this allows us to interpret expressions involving inverse functions as angles.

Right Triangle Relationships

Using the value of cos(θ) = adjacent/hypotenuse, we can construct a right triangle with sides 3 (adjacent) and 5 (hypotenuse). The Pythagorean theorem helps find the opposite side, enabling us to find sin(θ) based on triangle side ratios.

Pythagorean Identity

The Pythagorean identity states sin²(θ) + cos²(θ) = 1. Given cos(θ), we can find sin(θ) by rearranging to sin(θ) = ±√(1 - cos²(θ)). This identity is essential for finding the sine of an angle when only the cosine is known.

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Related Practice

Textbook Question

In Exercises 43–52, determine the amplitude, period, and phase shift of each function. Then graph one period of the function. y = 3 cos(2x − π)

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Textbook Question

In Exercises 39–54, find the exact value of each expression, if possible. Do not use a calculator. tan (tan⁻¹ 125)

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Textbook Question

In Exercises 29–51, find the exact value of each expression. Do not use a calculator. _ csc(tan⁻¹ √3/3)

Textbook Question

Determine the amplitude, period, and phase shift of each function. Then graph one period of the function.

y = cos(x + π/2)

Textbook Question

In Exercises 45–52, graph two periods of each function. y = sec(2x + π/2) − 1

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Textbook Question

Determine the amplitude, period, and phase shift of each function. Then graph one period of the function.

y = 4 cos(2x − π)

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