If vector and vector calculate using and notation.
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
- OLD 1. Angles and the Trigonometric Functions Coming soon
- OLD 2. Trigonometric Functions graphs, Inverse Trigonometric Functions Coming soon
- OLD 3. Trigonometric Identities and Equations Coming soon
- OLD 4. Laws of Sines, Cosines and Vectors Coming soon
- OLD 5. Complex Numbers, Polar Coordinates and Parametric Equations Coming soon
- NEW (not used) 7. Laws of Sines, Cosines and Vectors Coming soon
- NEW (not used) 8. Vectors Coming soon
- NEW(not used) 9. Polar equations Coming soon
- NEW (not used) 11. Graphing Complex Numbers Coming soon
8. Vectors
Unit Vectors and i & j Notation
Problem 42
Textbook Question
In Exercises 39–46, find the unit vector that has the same direction as the vector v.
v = 8i - 6j
Verified step by step guidance1
Identify the given vector \( \mathbf{v} = 8\mathbf{i} - 6\mathbf{j} \). This means the vector has components \( x = 8 \) and \( y = -6 \).
Calculate the magnitude (length) of the vector \( \mathbf{v} \) using the formula:
\[ \|\mathbf{v}\| = \sqrt{(x)^2 + (y)^2} = \sqrt{8^2 + (-6)^2} \]
Simplify the expression under the square root to find the magnitude:
\[ \|\mathbf{v}\| = \sqrt{64 + 36} \]
To find the unit vector in the same direction as \( \mathbf{v} \), divide each component of \( \mathbf{v} \) by its magnitude:
\[ \mathbf{u} = \left( \frac{8}{\|\mathbf{v}\|}, \frac{-6}{\|\mathbf{v}\|} \right) \]
Express the unit vector \( \mathbf{u} \) in terms of \( \mathbf{i} \) and \( \mathbf{j} \):
\[ \mathbf{u} = \frac{8}{\|\mathbf{v}\|} \mathbf{i} - \frac{6}{\|\mathbf{v}\|} \mathbf{j} \]
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Vector Components and Notation
A vector in two dimensions is expressed using unit vectors i and j, representing the x and y directions respectively. For example, v = 8i - 6j means the vector has an x-component of 8 and a y-component of -6. Understanding this notation is essential for manipulating and analyzing vectors.
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i & j Notation
Magnitude of a Vector
The magnitude (or length) of a vector v = ai + bj is found using the Pythagorean theorem: |v| = √(a² + b²). This scalar value represents the distance from the origin to the point defined by the vector components and is crucial for normalizing vectors.
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Finding Magnitude of a Vector
Unit Vector and Direction
A unit vector has a magnitude of 1 and points in the same direction as the original vector. It is found by dividing each component of the vector by its magnitude, effectively scaling the vector to length one while preserving direction.
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Finding Direction of a Vector
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