Given the polar equation , which of the following is the corresponding Cartesian equation?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
- OLD 1. Angles and the Trigonometric Functions Coming soon
- OLD 2. Trigonometric Functions graphs, Inverse Trigonometric Functions Coming soon
- OLD 3. Trigonometric Identities and Equations Coming soon
- OLD 4. Laws of Sines, Cosines and Vectors Coming soon
- OLD 5. Complex Numbers, Polar Coordinates and Parametric Equations Coming soon
- NEW (not used) 7. Laws of Sines, Cosines and Vectors Coming soon
- NEW (not used) 8. Vectors Coming soon
- NEW(not used) 9. Polar equations Coming soon
- NEW (not used) 11. Graphing Complex Numbers Coming soon
9. Polar Equations
Polar Coordinate System
Problem 6
Textbook Question
In Exercises 1–8, parametric equations and a value for the parameter t are given. Find the coordinates of the point on the plane curve described by the parametric equations corresponding to the given value of t. x = 2 + 3 cos t, y = 4 + 2 sin t; t = π
Verified step by step guidance1
Identify the parametric equations given: \(x = 2 + 3 \cos t\) and \(y = 4 + 2 \sin t\).
Substitute the given value of the parameter \(t = \pi\) into the equation for \(x\): calculate \(x = 2 + 3 \cos \pi\).
Recall the value of \(\cos \pi\), which is \(-1\), and use it to simplify the expression for \(x\).
Substitute the same value \(t = \pi\) into the equation for \(y\): calculate \(y = 4 + 2 \sin \pi\).
Recall the value of \(\sin \pi\), which is \(0\), and use it to simplify the expression for \(y\). The coordinates of the point are then \((x, y)\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Parametric Equations
Parametric equations express the coordinates of points on a curve as functions of a parameter, often denoted as t. Instead of y as a function of x, both x and y depend on t, allowing the description of more complex curves like ellipses or circles.
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Parameterizing Equations
Evaluating Trigonometric Functions at Specific Angles
To find coordinates for a given parameter t, substitute t into the trigonometric functions (cos t and sin t). Knowing exact values of sine and cosine at common angles like π is essential for accurate calculation of points on the curve.
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Coordinate Calculation from Parametric Form
Once the parameter value is substituted, calculate x and y by evaluating the expressions. This process converts the parametric form into a specific point (x, y) on the plane, representing the location on the curve at that parameter.
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