Which statement proves that triangle is an isosceles right triangle?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
- OLD 1. Angles and the Trigonometric Functions Coming soon
- OLD 2. Trigonometric Functions graphs, Inverse Trigonometric Functions Coming soon
- OLD 3. Trigonometric Identities and Equations Coming soon
- OLD 4. Laws of Sines, Cosines and Vectors Coming soon
- OLD 5. Complex Numbers, Polar Coordinates and Parametric Equations Coming soon
- NEW (not used) 7. Laws of Sines, Cosines and Vectors Coming soon
- NEW (not used) 8. Vectors Coming soon
- NEW(not used) 9. Polar equations Coming soon
- NEW (not used) 11. Graphing Complex Numbers Coming soon
2. Trigonometric Functions on Right Triangles
Solving Right Triangles
Multiple Choice
A right triangle has a base of units and the angle opposite the height is . What is the height of the triangle?
A
units
B
units
C
units
D
units
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Verified step by step guidance1
Identify the given elements in the right triangle: the base length is 68 units, and the angle opposite the height (which is the side we want to find) is 15 degrees.
Recall that in a right triangle, the sine of an angle is the ratio of the length of the side opposite the angle to the hypotenuse. However, here we have the base (adjacent side) and want the height (opposite side), so we can use the tangent function instead.
Write the tangent function for the 15° angle: \(\tan(15^\circ) = \frac{\text{height}}{\text{base}}\).
Substitute the known base length into the equation: \(\tan(15^\circ) = \frac{\text{height}}{68}\).
Solve for the height by multiplying both sides by 68: \(\text{height} = 68 \times \tan(15^\circ)\).
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