Given two unit vectors and on the unit circle, what is the angle between them if = and = ? Express your answer using one significant figure.
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
- OLD 1. Angles and the Trigonometric Functions Coming soon
- OLD 2. Trigonometric Functions graphs, Inverse Trigonometric Functions Coming soon
- OLD 3. Trigonometric Identities and Equations Coming soon
- OLD 4. Laws of Sines, Cosines and Vectors Coming soon
- OLD 5. Complex Numbers, Polar Coordinates and Parametric Equations Coming soon
- NEW (not used) 7. Laws of Sines, Cosines and Vectors Coming soon
- NEW (not used) 8. Vectors Coming soon
- NEW(not used) 9. Polar equations Coming soon
- NEW (not used) 11. Graphing Complex Numbers Coming soon
3. Unit Circle
Trigonometric Functions on the Unit Circle
Multiple Choice
For which values of is the expression defined on the unit circle?
A
For all such that
B
For all such that and
C
For all such that
D
For all real values of
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Verified step by step guidance1
Identify the given expression: \(\sec^{2}(\theta) \cdot \cos(2\theta)\). We want to find for which values of \(\theta\) this expression is defined on the unit circle.
Recall that \(\sec(\theta) = \frac{1}{\cos(\theta)}\). Therefore, \(\sec^{2}(\theta) = \frac{1}{\cos^{2}(\theta)}\). This means the expression is undefined wherever \(\cos(\theta) = 0\) because division by zero is undefined.
Next, consider the factor \(\cos(2\theta)\). Since cosine is defined for all real numbers, \(\cos(2\theta)\) itself does not cause any undefined values. However, if \(\cos(2\theta) = 0\), the product will be zero, which is defined, so no restriction arises here.
Summarize the domain restrictions: The expression is undefined when \(\cos(\theta) = 0\). Therefore, the expression is defined for all \(\theta\) such that \(\cos(\theta) \neq 0\).
Conclude that the expression is defined for all \(\theta\) on the unit circle except where \(\cos(\theta) = 0\), which corresponds to \(\theta = \frac{\pi}{2} + k\pi\), where \(k\) is any integer.
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