Given that angle is in standard position and its terminal side passes through the point , which is the best approximation for the measure of angle in degrees?
Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles40m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
- OLD 1. Angles and the Trigonometric Functions Coming soon
- OLD 2. Trigonometric Functions graphs, Inverse Trigonometric Functions Coming soon
- OLD 3. Trigonometric Identities and Equations Coming soon
- OLD 4. Laws of Sines, Cosines and Vectors Coming soon
- OLD 5. Complex Numbers, Polar Coordinates and Parametric Equations Coming soon
- NEW (not used) 7. Laws of Sines, Cosines and Vectors Coming soon
- NEW (not used) 8. Vectors Coming soon
- NEW(not used) 9. Polar equations Coming soon
- NEW (not used) 11. Graphing Complex Numbers Coming soon
1. Measuring Angles
Angles in Standard Position
Multiple Choice
An angle in standard position has its initial side along the positive -axis and its terminal side passes through the point on the unit circle. What is the measurement of this angle in degrees?
A
degrees
B
degrees
C
degrees
D
degrees
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Verified step by step guidance1
Identify that the angle is in standard position, meaning its initial side lies along the positive x-axis.
Recognize that the terminal side of the angle passes through the point (0, 1) on the unit circle.
Recall that points on the unit circle correspond to angles where the coordinates are (cos \(\theta\), sin \(\theta\)).
Since the point is (0, 1), set cos \(\theta\) = 0 and sin \(\theta\) = 1, and determine which angle \(\theta\) satisfies these conditions.
Use the unit circle knowledge to conclude that the angle with cos \(\theta\) = 0 and sin \(\theta\) = 1 is \(\theta\) = 90^{\(\circ\)}.
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