Consider the set of ordered pairs. Verify if it is one-to-one. If so, find its inverse.
$g=\left\{\right(1,\frac{3}{2}),(4,\frac{5}{3}),(7,\frac{9}{4}),(10,\frac{11}{6}\left)\right\}$

$g^{-1}=\left\{\right(1,\frac{2}{3}),(\frac{1}{4},\frac{3}{5}),(\frac{1}{7},\frac{4}{9}),(\frac{1}{10},\frac{6}{11}\left)\right\}$

$g^{-1}=\left\{\right(\frac{2}{3},1),(\frac{3}{5},\frac{1}{4}),(\frac{4}{9},\frac{1}{7}),(\frac{6}{11},\frac{1}{10}\left)\right\}$

$g^{-1}=\left\{\right(\frac{3}{2},1),(\frac{5}{3},4),(\frac{9}{4},7),(\frac{11}{6},10\left)\right\}$

The function is not one-to-one.