A thin lens with a focal length of 6.00 cm is used as a simple magnifier. What angular magnification is obtainable with the lens if the object is at the focal point?
Ch 34: Geometric Optics
Young & Freedman Calc15th EditionUniversity PhysicsISBN: 9780135159552Not the one you use?Change textbook
Chapter 33, Problem 59b
The focal length of a simple magnifier is 8.00 cm. Assume the magnifier is a thin lens placed very close to the eye. If the object is 1.00 mm high, what is the height of its image formed by the magnifier?
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Identify the given values: The focal length of the lens \( f = 8.00 \; \text{cm} \) and the object height \( h_o = 1.00 \; \text{mm} \). The goal is to find the height of the image \( h_i \).
Use the lens formula to find the image distance \( v \): \( \frac{1}{f} = \frac{1}{u} + \frac{1}{v} \), where \( f \) is the focal length, \( u \) is the object distance, and \( v \) is the image distance. Rearrange to solve for \( v \): \( \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \).
Determine the magnification \( M \) of the lens using the formula \( M = \frac{h_i}{h_o} = \frac{v}{u} \). Rearrange to solve for \( h_i \): \( h_i = M \cdot h_o \).
Substitute the values of \( v \), \( u \), and \( h_o \) into the magnification formula to calculate the image height \( h_i \). Ensure that all units are consistent (e.g., convert \( h_o \) to cm if necessary).
Interpret the result: The sign of \( h_i \) will indicate whether the image is upright or inverted, and the magnitude will give the size of the image formed by the magnifier.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Focal Length
The focal length of a lens is the distance from the lens to the focal point, where parallel rays of light converge. For a simple magnifier, a positive focal length indicates that it is a converging lens. The focal length is crucial for determining how the lens will magnify an object and affects the size of the image formed.
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Magnification
Magnification is the ratio of the height of the image to the height of the object. It can be calculated using the formula: magnification (M) = image height (h') / object height (h). In the case of a magnifier, the magnification also depends on the focal length and the distance of the object from the lens, allowing us to determine how much larger the image appears compared to the actual object.
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Thin Lens Formula
The thin lens formula relates the object distance (d_o), image distance (d_i), and focal length (f) of a lens: 1/f = 1/d_o + 1/d_i. This formula is essential for understanding how lenses form images and can be used to find the image distance when the object distance and focal length are known. It helps in calculating the position and size of the image produced by the magnifier.
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Related Practice
Textbook Question
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Textbook Question
BIO A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision. Is she nearsighted or farsighted?
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Textbook Question
A telescope is constructed from two lenses with focal lengths of 95.0 cm and 15.0 cm, the 95.0 cm lens being used as the objective. Both the object being viewed and the final image are at infinity. Find the height of the image formed by the objective of a building 60.0 m tall, 3.00 km away.
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Textbook Question
BIO A person can see clearly up close but cannot focus on objects beyond 75.0 cm. She opts for contact lenses to correct her vision. What focal length contact lens is needed, and what is its power in diopters?
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