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Ch 43: Nuclear Physics
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 43, Problem 30

At an archeological site, a sample from timbers containing 500500 g of carbon provides 26902690 decays/min. What is the age of the sample?

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Step 1: Understand the problem. The sample contains carbon, and the decay rate is given. This problem involves radioactive decay, specifically carbon-14 dating. The goal is to calculate the age of the sample using the decay rate and the known properties of carbon-14.
Step 2: Recall the formula for radioactive decay: \( N(t) = N_0 e^{-\lambda t} \), where \( N(t) \) is the number of decays per unit time at time \( t \), \( N_0 \) is the initial decay rate, \( \lambda \) is the decay constant, and \( t \) is the time elapsed. For carbon-14, the half-life \( T_{1/2} \) is approximately 5730 years.
Step 3: Relate the decay constant \( \lambda \) to the half-life using the formula \( \lambda = \frac{\ln(2)}{T_{1/2}} \). Substitute \( T_{1/2} = 5730 \) years to calculate \( \lambda \).
Step 4: Use the given decay rate (2690 decays/min) and the initial decay rate (which can be calculated based on the mass of carbon and the known decay rate per gram for fresh carbon-14) to find \( t \). Rearrange the decay formula to solve for \( t \): \( t = \frac{-\ln\left(\frac{N(t)}{N_0}\right)}{\lambda} \).
Step 5: Substitute the values for \( N(t) \), \( N_0 \), and \( \lambda \) into the formula. Perform the logarithmic and division operations to determine the age of the sample.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Radioactive Decay

Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This decay occurs at a predictable rate, characterized by the half-life, which is the time required for half of the radioactive atoms in a sample to decay. Understanding this concept is crucial for determining the age of archaeological samples through techniques like carbon dating.
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Carbon-14 Dating

Carbon-14 dating is a method used to determine the age of organic materials by measuring the amount of carbon-14, a radioactive isotope of carbon, remaining in the sample. Living organisms continuously exchange carbon with their environment, but once they die, the carbon-14 begins to decay. By comparing the remaining carbon-14 to the initial levels, scientists can estimate the time since the organism's death.
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Decay Rate and Activity

The decay rate, or activity, of a radioactive sample is measured in decays per minute (dpm) and indicates how many atoms decay in a given time frame. This rate decreases over time as the radioactive material diminishes. In carbon dating, the activity of the sample is compared to a standard reference to calculate its age, making it essential to understand how to interpret these measurements.
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Related Practice
Textbook Question

In a diagnostic x-ray procedure, 5.00×10105.00\(\times\)10^{10} photons are absorbed by tissue with a mass of 0.6000.600 kg. The x-ray wavelength is 0.0200 0.0200 nm.

(a) What is the total energy absorbed by the tissue?

(b) What is the equivalent dose in rem?

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Textbook Question

Measurements on a certain isotope tell you that the decay rate decreases from 83188318 decays/min to 30913091 decays/min in 4.004.00 days. What is the half-life of this isotope?

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Textbook Question

The common isotope of uranium, 238U^{238}U, has a half-life of 4.47×1094.47\(\times\)10^9 years, decaying to 234Th^{234}Th by alpha emission.

(a) What is the decay constant?

(b) What mass of uranium is required for an activity of 1.001.00 curie?

(c) How many alpha particles are emitted per second by 10.010.0 g of uranium?

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Textbook Question

The unstable isotope 40K^{40}K is used for dating rock samples. Its half-life is 1.28×1091.28\(\times\)10^9 y.

(a) How many decays occur per second in a sample containing 1.63×1061.63\(\times\)10^{-6} g of 40K^{40}K?

(b) What is the activity of the sample in curies?

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Textbook Question

A 6767-kg person accidentally ingests 0.350.35 Ci of tritium.

(a) Assume that the tritium spreads uniformly throughout the body and that each decay leads on the average to the absorption of 5.05.0 keV of energy from the electrons emitted in the decay. The half-life of tritium is 12.312.3 y, and the RBE of the electrons is 1.01.0. Calculate the absorbed dose in rad and the equivalent dose in rem during one week.

(b) The β\(\beta\)^{-} decay of tritium releases more than 5.05.0 keV of energy. Why is the average energy absorbed less than the total energy released in the decay?

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Textbook Question

It has become popular for some people to have yearly whole-body scans (CT scans, formerly called CAT scans) using x rays, just to see if they detect anything suspicious. A number of medical people have recently questioned the advisability of such scans, due in part to the radiation they impart. Typically, one such scan gives a dose of 1212 mSv, applied to the whole body. By contrast, a chest x ray typically administers 0.200.20 mSv to only 5.05.0 kg of tissue. How many chest x rays would deliver the same total amount of energy to the body of a 7575-kg person as one whole-body scan?

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