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Ch 42: Molecules and Condensed Matter
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 42, Problem 24

At the Fermi temperature TFT_F, EF=kTFE_F = kT_F (see Exercise 42.2242.22). When T=TFT = T_F, what is the probability that a state with energy E=2EFE = 2E_F is occupied?

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Understand the problem: The Fermi-Dirac distribution function gives the probability that a quantum state with energy E is occupied at a given temperature T. The formula is: f(E)=11+e(EEF)/kT, where E is the energy of the state, E_F is the Fermi energy, k is the Boltzmann constant, and T is the temperature.
Substitute the given conditions: At the Fermi temperature T = T_F, and the energy of the state is E = 2E_F. Substitute these values into the Fermi-Dirac distribution formula: f(2EF)=11+e(2EFEF)/kT).
Simplify the exponent: Since E = 2E_F and T = T_F, the exponent becomes: (2EFEF)/kT). Simplify this to: (EF/kT). Since T = T_F, and by definition EF=kTF, the exponent simplifies further to 1.
Substitute the simplified exponent back into the Fermi-Dirac formula: The probability becomes: f(2EF)=11+e1.
Interpret the result: The probability is now expressed in terms of a simple fraction involving the exponential function. You can leave it in this form or calculate the numerical value if needed, but the key takeaway is that the probability decreases significantly for states with energy much higher than the Fermi energy at the Fermi temperature.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Fermi Temperature (T_F)

The Fermi temperature is a characteristic temperature associated with a system of fermions, such as electrons in a metal. It is defined as T_F = E_F / k, where E_F is the Fermi energy and k is the Boltzmann constant. At this temperature, the thermal energy is comparable to the energy levels of the particles, influencing their occupancy in quantum states.
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Fermi Energy (E_F)

Fermi energy is the highest energy level occupied by fermions at absolute zero temperature. It represents the energy of the most energetic electrons in a system and is crucial for understanding the distribution of particles in a quantum system. At temperatures near T_F, the occupancy of states can be analyzed using the Fermi-Dirac distribution.
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Fermi-Dirac Distribution

The Fermi-Dirac distribution describes the statistical distribution of particles over energy states in systems of indistinguishable fermions. It accounts for the Pauli exclusion principle, which states that no two fermions can occupy the same quantum state. The probability of occupancy of a state with energy E at temperature T is given by f(E) = 1 / (e^(E - μ)/(kT) + 1), where μ is the chemical potential.
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Related Practice
Textbook Question

Suppose a piece of very pure germanium is to be used as a light detector by observing, through the absorption of photons, the increase in conductivity resulting from generation of electron–hole pairs. If each pair requires 0.670.67 eV of energy, what is the maximum wavelength that can be detected? In what portion of the spectrum does it lie?

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Textbook Question

Calculate the density of states g(E)g(E) for the free-electron model of a metal if E=7.0E = 7.0 eV and V=1.0V = 1.0 cm3. Express your answer in units of states per electron volt.

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Textbook Question

At a temperature of 290 290 K, a certain pnp-n junction has a saturation current IS=0.500I_S = 0.500 mA. Find the current at this temperature when the voltage is (i) 1.001.00 mV, (ii) 1.00-1.00 mV, (iii) 100100 mV, and (iv) 100-100 mV.

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Textbook Question

Silver has a Fermi energy of 5.485.48 eV. Calculate the electron contribution to the molar heat capacity at constant volume of silver, CVC_V, at 300300 K. Express your result as a multiple of RR.

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Textbook Question

Pure germanium has a band gap of 0.670.67 eV. The Fermi energy is in the middle of the gap. For temperatures of 250250 K, 300300 K, and 350350 K, calculate the probability f(E)f(E) that a state at the bottom of the conduction band is occupied.

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Textbook Question

The maximum wavelength of light that a certain silicon photocell can detect is 1.111.11 mm. What is the energy gap (in electron volts) between the valence and conduction bands for this photocell?

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