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Ch 39: Particles Behaving as Waves
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 39, Problem 30

Use Balmer's formula to calculate (a) the wavelength, (b) the frequency, and (c) the photon energy for the Hg line of the Balmer series for hydrogen.

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Step 1: Understand Balmer's formula. Balmer's formula is used to calculate the wavelength of spectral lines in the hydrogen atom. It is given by: λn=R(n2)n2-m2, where R is the Rydberg constant (approximately 1.097 × 10⁷ m⁻¹), n is the principal quantum number of the final energy level, and m is the principal quantum number of the initial energy level. For the Balmer series, m = 2.
Step 2: Identify the quantum numbers for the Hg line in the Balmer series. The Hg line corresponds to the transition where the electron moves from n = 4 to m = 2. Substitute these values into Balmer's formula to calculate the wavelength: λn=R(42)42-22.
Step 3: Once the wavelength is determined, calculate the frequency using the relationship between wavelength and frequency: f=cλ, where c is the speed of light (approximately 3 × 10⁸ m/s). Substitute the calculated wavelength into this formula to find the frequency.
Step 4: Calculate the photon energy using the formula: E=hf, where h is Planck's constant (approximately 6.626 × 10⁻³⁴ J·s) and f is the frequency calculated in the previous step.
Step 5: Summarize the results. You now have the wavelength, frequency, and photon energy for the Hg line of the Balmer series. Ensure all units are consistent and verify the calculations for accuracy.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Balmer's Formula

Balmer's formula describes the wavelengths of the spectral lines in the hydrogen atom's Balmer series. It is given by the equation λ = b(n²)/(n² - 2²), where λ is the wavelength, b is a constant (approximately 364.50682 nm), and n is the principal quantum number (n = 3, 4, 5, ...). This formula allows us to calculate the wavelengths of light emitted when electrons transition from higher energy levels to the second energy level.
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Frequency and Wavelength Relationship

The frequency (ν) of a wave is inversely related to its wavelength (λ) through the equation c = νλ, where c is the speed of light (approximately 3.00 x 10^8 m/s). This relationship indicates that as the wavelength increases, the frequency decreases, and vice versa. Understanding this concept is essential for calculating the frequency of the emitted light from the wavelength obtained using Balmer's formula.
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Photon Energy

The energy (E) of a photon is directly proportional to its frequency and is given by the equation E = hν, where h is Planck's constant (approximately 6.626 x 10^-34 J·s). This relationship shows that higher frequency light corresponds to higher energy photons. Calculating the photon energy for the emitted light from the Balmer series requires knowing the frequency derived from the wavelength.
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Related Practice
Textbook Question

How many photons per second are emitted by a 7.507.50-mW CO2 laser that has a wavelength of 10.610.6 mm?

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Textbook Question

Photorefractive keratectomy (PRK) is a laser-based surgical procedure that corrects near- and farsightedness by removing part of the lens of the eye to change its curvature and hence focal length. This procedure can remove layers 0.250.25 mm thick using pulses lasting 12.012.0 ns from a laser beam of wavelength 193193 nm. Low-intensity beams can be used because each individual photon has enough energy to break the covalent bonds of the tissue. If a 1.501.50-mW beam is used, how many photons are delivered to the lens in each pulse?

Textbook Question

In a set of experiments on a hypothetical one-electron atom, you measure the wavelengths of the photons emitted from transitions ending in the ground level (n=1n = 1), as shown in the energy-level diagram in Fig. E39.2739.27. You also observe that it takes 17.5017.50 eV to ionize this atom. What is the energy of the atom in each of the levels (n=1n = 1, n=2n = 2, etc.) shown in the figure?

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Textbook Question

The energy-level scheme for the hypothetical one-electron element Searsium is shown in Fig. E39.25E39.25. The potential energy is taken to be zero for an electron at an infinite distance from the nucleus. An 1818-eV photon is absorbed by a Searsium atom in its ground level. As the atom returns to its ground level, what possible energies can the emitted photons have? Assume that there can be transitions between all pairs of levels.

Textbook Question

Using a mixture of CO2, N2, and sometimes He, CO2 lasers emit a wavelength of 10.610.6 μ\(\mu\)m. At power of 0.1000.100 kW, such lasers are used for surgery. How many photons per second does a CO2 laser deliver to the tissue during its use in an operation?

Textbook Question

Find the longest and shortest wavelengths in the Lyman and Paschen series for hydrogen. In what region of the electromagnetic spectrum does each series lie?