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Ch 03: Motion in Two or Three Dimensions
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
All textbooksYoung & Freedman Calc 14th EditionCh 03: Motion in Two or Three DimensionsProblem 30a
Chapter 3, Problem 30a

A railroad flatcar is traveling to the right at a speed of 13.0 m/s relative to an observer standing on the ground. Someone is riding a motor scooter on the flatcar (Fig. E3.30). What is the velocity (magnitude and direction) of the scooter relative to the flatcar if the scooter's velocity relative to the observer on the ground is 18.0 m/s to the right?

Verified step by step guidance
1
Identify the given velocities: The velocity of the flatcar relative to the ground is 13.0 m/s to the right, and the velocity of the scooter relative to the ground is 18.0 m/s to the right.
Understand the concept of relative velocity: The velocity of the scooter relative to the flatcar is the difference between the velocity of the scooter relative to the ground and the velocity of the flatcar relative to the ground.
Set up the equation for relative velocity: Let v_s/f be the velocity of the scooter relative to the flatcar. Then, v_s/f = v_s/g - v_f/g, where v_s/g is the velocity of the scooter relative to the ground, and v_f/g is the velocity of the flatcar relative to the ground.
Substitute the given values into the equation: v_s/f = 18.0 m/s - 13.0 m/s.
Solve the equation to find the velocity of the scooter relative to the flatcar. The result will give you both the magnitude and direction of the scooter's velocity relative to the flatcar.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Relative Velocity

Relative velocity is the velocity of an object as observed from a particular reference frame. It is calculated by subtracting the velocity of the observer from the velocity of the object. In this problem, the velocity of the scooter relative to the flatcar is found by subtracting the flatcar's velocity from the scooter's velocity as observed from the ground.
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Intro to Relative Motion (Relative Velocity)

Reference Frames

A reference frame is a perspective from which motion is observed and measured. In this scenario, there are two reference frames: one is the ground observer's frame, and the other is the flatcar's frame. Understanding how velocities transform between these frames is crucial for solving the problem.
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Vector Addition

Vector addition is a method used to combine vectors, which have both magnitude and direction. In this context, the velocities are vectors, and the relative velocity is determined by vector subtraction, which is a form of vector addition where one vector is added in the opposite direction. This helps in finding the scooter's velocity relative to the flatcar.
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Related Practice
Textbook Question

Two piers, A and B, are located on a river; B is 1500 m downstream from A (Fig. E3.32). Two friends must make round trips from pier A to pier B and return. One rows a boat at a constant speed of 4.00 km/h relative to the water; the other walks on the shore at a constant speed of 4.00 km/h. The velocity of the river is 2.80 km/h in the direction from A to B. How much time does it take each person to make the round trip?


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Textbook Question

At its Ames Research Center, NASA uses its large '20-G' centrifuge to test the effects of very large accelerations ('hypergravity') on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. How fast must the astronaut's head be moving to experience this maximum acceleration?

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Textbook Question

At its Ames Research Center, NASA uses its large '20-G' centrifuge to test the effects of very large accelerations ('hypergravity') on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. How fast in rpm (rev/min) is the arm turning to produce the maximum sustained acceleration?

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Textbook Question

At its Ames Research Center, NASA uses its large '20-G' centrifuge to test the effects of very large accelerations ('hypergravity') on test pilots and astronauts. In this device, an arm 8.84 m long rotates about one end in a horizontal plane, and an astronaut is strapped in at the other end. Suppose that he is aligned along the centrifuge's arm with his head at the outermost end. The maximum sustained acceleration to which humans are subjected in this device is typically 12.5g. What is the difference between the acceleration of his head and feet if the astronaut is 2.00 m tall?

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Textbook Question

A 'moving sidewalk' in an airport terminal moves at 1.0 m/s and is 35.0 m long. If a woman steps on at one end and walks at 1.5 m/s relative to the moving sidewalk, how much time does it take her to reach the opposite end if she walks In the opposite direction?

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Textbook Question

A 'moving sidewalk' in an airport terminal moves at 1.0 m/s and is 35.0 m long. If a woman steps on at one end and walks at 1.5 m/s relative to the moving sidewalk, how much time does it take her to reach the opposite end if she walks in the same direction the sidewalk is moving?

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