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Ch 02: Motion Along a Straight Line
Young & Freedman Calc - University Physics 14th Edition
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 2, Problem 49

You throw a small rock straight up from the edge of a highway bridge that crosses a river. The rock passes you on its way down, 6.006.00 s after it was thrown. What is the speed of the rock just before it reaches the water 28.028.0 m below the point where the rock left your hand? Ignore air resistance.

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1
Identify the known values: the time taken for the rock to pass you on its way down is 6.00 s, and the distance from the bridge to the water is 28.0 m. We need to find the speed of the rock just before it reaches the water.
Use the kinematic equation for vertical motion: vf=vi+gt, where vf is the final velocity, vi is the initial velocity, g is the acceleration due to gravity (approximately 9.81 m/s²), and t is the time.
Since the rock passes you on its way down after 6.00 s, the initial velocity vi can be found using the equation y=vit+12gt2, where y is the displacement (28.0 m).
Rearrange the equation to solve for vi: vi=y-12gt2t. Substitute the known values to find vi.
Finally, substitute the initial velocity vi and the time t into the kinematic equation to find the final velocity vf just before the rock reaches the water.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Kinematics Equations

Kinematics equations describe the motion of objects under constant acceleration. In this scenario, the rock's motion can be analyzed using these equations to determine its velocity and position at different times. The key equations include those for displacement, velocity, and acceleration, which help calculate the rock's speed just before it hits the water.
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Gravitational Acceleration

Gravitational acceleration is the constant acceleration experienced by objects due to Earth's gravity, approximately 9.81 m/s². This concept is crucial for calculating the rock's motion as it travels upwards and then downwards. Understanding gravitational acceleration allows us to determine how the rock's velocity changes over time.
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Initial Velocity

Initial velocity is the speed at which an object begins its motion. In this problem, the rock is thrown upwards, and its initial velocity affects its subsequent motion. Knowing the initial velocity helps in applying kinematics equations to find the rock's speed at different points, including just before it reaches the water.
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Related Practice
Textbook Question

High-speed motion pictures (35003500 frames/second) of a jumping, 210μg210–μg flea yielded the data used to plot the graph in Fig. E2.542.54. (See 'The Flying Leap of the Flea' by M. Rothschild, Y. Schlein, K. Parker, C. Neville, and S. Sternberg in the November 19731973 Scientific American.) This flea was about 22 mm long and jumped at a nearly vertical takeoff angle. Use the graph to answer this question: Is the acceleration of the flea ever zero? If so, when? Justify your answer.

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Textbook Question

A large boulder is ejected vertically upward from a volcano with an initial speed of 40.040.0 m/s. Ignore air resistance. When is the velocity of the boulder zero?

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Textbook Question

A rocket starts from rest and moves upward from the surface of the earth. For the first 10.010.0 s of its motion, the vertical acceleration of the rocket is given by ay=(2.80a_{y}=(2.80 m/s3)t)t, where the +y+y-direction is upward. What is the height of the rocket above the surface of the earth at t=10.0t = 10.0 s?

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Textbook Question

A large boulder is ejected vertically upward from a volcano with an initial speed of 40.040.0 m/s. Ignore air resistance. What are the magnitude and direction of the acceleration while the boulder is (i) moving upward? (ii) Moving downward? (iii) At the highest point?

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Textbook Question

A large boulder is ejected vertically upward from a volcano with an initial speed of 40.040.0 m/s. Ignore air resistance. When is the displacement of the boulder from its initial position zero?

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Textbook Question

A rocket starts from rest and moves upward from the surface of the earth. For the first 10.010.0 s of its motion, the vertical acceleration of the rocket is given by ay=(2.80a_{y}=(2.80 m/s3)t)t, where the +y+y-direction is upward. What is the speed of the rocket when it is 325325 m above the surface of the earth?

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