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Ch.8 - Reactions of Alkenes
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
All textbooksWade 9th EditionCh.8 - Reactions of AlkenesProblem 21c,d
Chapter 8, Problem 21c,d

Predict the major product(s) for each reaction. Include stereochemistry where appropriate.
c. cis-but-2-ene + Cl2/H2O
d. trans-but-2-ene + Cl2/H2O

Verified step by step guidance
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Step 1: Recognize the reaction type. The reaction involves an alkene (cis-but-2-ene or trans-but-2-ene) reacting with Cl₂ in the presence of H₂O. This is a halohydrin formation reaction, where the alkene undergoes electrophilic addition to form a halohydrin (a molecule containing both a halogen and a hydroxyl group).
Step 2: Analyze the mechanism. The reaction proceeds via the formation of a cyclic chloronium ion intermediate. The π-electrons of the alkene attack the Cl₂ molecule, leading to the formation of the cyclic intermediate and a chloride ion (Cl⁻).
Step 3: Determine the regioselectivity. The water molecule (H₂O) acts as a nucleophile and attacks the more substituted carbon of the cyclic chloronium ion. This occurs because the more substituted carbon is better able to stabilize the partial positive charge in the transition state.
Step 4: Consider stereochemistry. For cis-but-2-ene, the addition of Cl and OH groups will occur in an anti fashion (opposite sides of the double bond plane). Similarly, for trans-but-2-ene, the anti addition will also occur, but the stereochemistry of the product will differ due to the initial geometry of the alkene.
Step 5: Draw the products. For cis-but-2-ene, the major product will be a pair of enantiomers (R,S and S,R configurations) due to anti addition. For trans-but-2-ene, the major product will also be a pair of enantiomers (R,R and S,S configurations). Ensure to include the correct stereochemistry in the final structures.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electrophilic Addition Reactions

Electrophilic addition reactions involve the addition of an electrophile to a nucleophile, typically across a double bond. In the case of alkenes, the π bond is broken, allowing for the formation of new σ bonds. Understanding this mechanism is crucial for predicting the products of reactions involving alkenes, such as the addition of Cl2 and H2O to but-2-ene.
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Stereochemistry

Stereochemistry refers to the spatial arrangement of atoms in molecules and how this affects their chemical behavior. In reactions involving alkenes, the formation of chiral centers can lead to different stereoisomers. Recognizing the stereochemical outcomes, especially in reactions with reagents like Cl2 and H2O, is essential for accurately predicting the major products.
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Markovnikov's Rule

Markovnikov's Rule states that in the addition of HX to an alkene, the hydrogen atom will attach to the carbon with the greater number of hydrogen atoms already attached. This principle helps predict the regioselectivity of electrophilic addition reactions, such as the addition of Cl2 and H2O to but-2-ene, guiding the formation of the major product based on the stability of the resulting carbocation.
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Related Practice
Textbook Question

Show how you would accomplish the following synthetic conversions.

a. 3-methylpent-2-ene → 2-chloro-3-methylpentan-3-ol

Problem-Solving Hint: The opening of a halonium ion is driven by its electrophilic nature. The weak nucleophile attacks the carbon bearing more positive charge.

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Textbook Question

Predict the major product(s) for each reaction. Include stereochemistry where appropriate.

e. 1-methylcyclopentene + Br2 in saturated aqueous NaCl

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Textbook Question

Show how you would accomplish the following synthetic conversions.

b. chlorocyclohexane → trans-2-chlorocyclohexanol

Problem-Solving Hint: The opening of a halonium ion is driven by its electrophilic nature. The weak nucleophile attacks the carbon bearing more positive charge.

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Textbook Question

The solutions to Solved Problem 8-5 showed only how one enantiomer of the product is formed. For each product, show how an equally probable reaction forms the other enantiomer.

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Textbook Question

The solutions to Solved Problem 8-6 showed only how one enantiomer of the product is formed. For each product, show how an equally probable reaction forms the other enantiomer.

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Textbook Question

Predict the major product(s) for each reaction. Include stereochemistry where appropriate.

a. 1-methylcyclohexene + Cl2/H2O

b. 2-methylbut-2-ene + Br2/H2O

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