Textbook Question
Draw the structure and give the molecular formula for each of the following compounds.
e. 3-ethyl-2,4-dimethylhexane
f. 1,1-diethyl-4-(3,3-dimethylbutyl)cyclohexane
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Ch.3 - Structure and Stereochemistry of Alkanes
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 3, Problem 17b
Which of the following cycloalkanes are capable of geometric (cis-trans) isomerism? Draw the cis and trans isomers.
b. 1-ethyl-3-methylcycloheptane
Verified step by step guidance1
Step 1: Understand the concept of geometric (cis-trans) isomerism. Geometric isomerism occurs in cycloalkanes when there are two substituents on different carbon atoms of the ring, and these substituents can be positioned either on the same side (cis) or on opposite sides (trans) of the ring.
Step 2: Analyze the structure of 1-ethyl-3-methylcycloheptane. This compound has a cycloheptane ring with an ethyl group at the first carbon and a methyl group at the third carbon.
Step 3: Determine if the substituents allow for cis-trans isomerism. For geometric isomerism to occur, the substituents must be on different carbon atoms and the ring must be large enough to accommodate the spatial arrangement. Cycloheptane is large enough to allow for this isomerism.
Step 4: Draw the cis isomer. In the cis isomer, both the ethyl and methyl groups are on the same side of the cycloheptane ring. Visualize or sketch the ring with both substituents pointing in the same direction.
Step 5: Draw the trans isomer. In the trans isomer, the ethyl and methyl groups are on opposite sides of the cycloheptane ring. Visualize or sketch the ring with one substituent pointing up and the other pointing down, ensuring they are on opposite sides.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Geometric Isomerism
Geometric isomerism, also known as cis-trans isomerism, occurs in compounds with restricted rotation around a bond, typically a double bond or a ring structure. It requires two substituents on each side of the bond or ring, allowing for different spatial arrangements. In cycloalkanes, this isomerism arises when substituents are positioned differently relative to the ring plane.
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Cycloalkane Structure
Cycloalkanes are saturated hydrocarbons with carbon atoms arranged in a ring. The ring structure restricts rotation, which can lead to geometric isomerism if substituents are present. The size and shape of the ring influence the stability and possibility of isomerism, with larger rings like cycloheptane being more flexible than smaller ones.
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Substituent Positioning
In cycloalkanes, the positioning of substituents determines the possibility of cis-trans isomerism. For 1-ethyl-3-methylcycloheptane, the ethyl and methyl groups must be on different carbons and can be arranged either on the same side (cis) or opposite sides (trans) of the ring plane. This spatial arrangement affects the compound's physical and chemical properties.
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Related Practice
Textbook Question
Which of the following cycloalkanes are capable of geometric (cis-trans) isomerism? Draw the cis and trans isomers.
c. 1-ethyl-3-methylcyclopentane
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Textbook Question
Draw the structure that corresponds with each name.
k. cyclobutylcyclohexane
l. cis-1-bromo-3-chlorocyclohexane
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Textbook Question
The heat of combustion of cis-1,2-dimethylcyclopropane is larger than that of the trans isomer. Which isomer is more stable? Use drawings to explain this difference in stability.
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Textbook Question
trans-1,2-Dimethylcyclobutane is more stable than cis-1,2-dimethylcyclobutane, but cis-1,3-dimethylcyclobutane is more stable than trans-1,3-dimethylcyclobutane. Use drawings to explain these observations.
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Textbook Question
Which of the following cycloalkanes are capable of geometric (cis-trans) isomerism? Draw the cis and trans isomers.
a. 3-ethyl-1,1-dimethylcyclohexane
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