Textbook Question
Show how you might synthesize the following compounds starting with bromobenzene, and alkyl or alkenyl halides of four carbon atoms or fewer.
c. dec-5-ene
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Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
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Wade 9th EditionCh. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet SpectroscopyProblem 13a
Wade 9th EditionCh. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet SpectroscopyProblem 13aChapter 15, Problem 13a
Show how you might synthesize the following compounds starting with bromobenzene, and alkyl or alkenyl halides of four carbon atoms or fewer.
a. 3-phenylprop-1-ene
Verified step by step guidance1
Step 1: Begin with bromobenzene (C6H5Br) as the starting material. Perform a Grignard reaction by reacting bromobenzene with magnesium (Mg) in dry ether to form phenylmagnesium bromide (C6H5MgBr). This is a key organometallic intermediate.
Step 2: Prepare propenal (CH2=CH-CHO), which is an alkenyl compound with three carbon atoms. This can be synthesized separately if not readily available.
Step 3: Perform a nucleophilic addition reaction between phenylmagnesium bromide (C6H5MgBr) and propenal (CH2=CH-CHO). The Grignard reagent will attack the carbonyl carbon of propenal, forming an intermediate alcohol.
Step 4: Dehydrate the intermediate alcohol to form 3-phenylprop-1-ene (C6H5-CH=CH-CH2). This can be achieved using an acid catalyst, such as concentrated sulfuric acid (H2SO4), to remove water and form the double bond.
Step 5: Purify the product using distillation or another appropriate method to isolate 3-phenylprop-1-ene. Confirm the structure using spectroscopic techniques such as NMR or IR.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Electrophilic Aromatic Substitution
Electrophilic aromatic substitution (EAS) is a fundamental reaction in organic chemistry where an electrophile replaces a hydrogen atom on an aromatic ring. In the context of synthesizing 3-phenylprop-1-ene from bromobenzene, EAS can be used to introduce a propyl group onto the benzene ring, forming a substituted aromatic compound that can further undergo elimination to yield the desired alkene.
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Alkylation Reactions
Alkylation reactions involve the introduction of an alkyl group into a molecule, often through nucleophilic substitution or EAS. In this synthesis, alkyl halides can react with bromobenzene to form a new carbon-carbon bond, which is crucial for building the propyl chain needed for 3-phenylprop-1-ene. Understanding the reactivity of alkyl halides is essential for selecting the appropriate reaction conditions.
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Elimination Reactions
Elimination reactions are processes where elements of the starting material are removed, resulting in the formation of a double bond. In synthesizing 3-phenylprop-1-ene, after the alkylation step, an elimination reaction can be performed to remove a leaving group and generate the alkene. This step is vital for achieving the final product with the desired double bond configuration.
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Related Practice
Textbook Question
When Br2 is added to buta-1,3-diene at –15 °C, the product mixture contains 60% of product A and 40% of product B. When the same reaction takes place at 60 °C, the product ratio is 10% A and 90% B.
d. If you had a solution of pure A, and its temperature were raised to 60 °C, what would you expect to happen? Propose a mechanism to support your prediction.
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Textbook Question
Predict the products of the following proposed Diels–Alder reactions.
(a)
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Textbook Question
Show how you might synthesize the following compounds starting with bromobenzene, and alkyl or alkenyl halides of four carbon atoms or fewer.
b. 5-methylhex-2-ene
Textbook Question
When N-bromosuccinimide is added to hex-1-ene in CCl4 and a sunlamp is shone on the mixture, three products result.
(a) Give the structures of these three products.
(b) Propose a mechanism that accounts for the formation of these three products
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Textbook Question
Addition of 1-bromobut-2-ene to magnesium metal in dry ether results in formation of a Grignard reagent. Addition of water to this Grignard reagent gives a mixture of but-1-ene and but-2-ene (cis and trans). When the Grignard reagent is made using 3-bromobut-1-ene, addition of water produces exactly the same mixture of products in the same ratios. Explain this curious result
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