Tributyltin hydride (Bu3SnH) is often used as a 'radical carrier' in radical reactions. Which bond would you expect to be weaker, Sn–H or C–H? How might this relate to radical stability? Explain your answer.

Mullins 1st Edition
Ch. 11 - Properties and Synthesis of Alkyl Halides: Radical Reactions
Problem 62aA halogenation intended to make compound A formed B instead.

(a) Suggest a mechanism for the intended formation of A.
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Key Concepts
Halogenation Reaction
Reaction Mechanism
Regioselectivity
Haloalkanes can be reduced to alkanes using radical reactions involving Bu₃SnH and a catalytic amount of AIBN. Suggest a mechanism for this reaction. [Pay close attention to the bonds formed and broken in developing your mechanism.]
Cyclizations can be carried out under radical conditions involving Bu₃SnH and a catalytic amount of AIBN. Suggest a mechanism for this reaction. [Pay close attention to the bonds formed and broken in developing your mechanism. It may be helpful to number the carbons.]
A halogenation intended to make compound A formed B instead.
(c) Given the two mechanisms you drew, why might B have formed selectively?
A halogenation intended to make compound A formed B instead.
(d) Without looking it up, would you expect C–Ha or C–Hb to have the lower bond-dissociation energy?
A halogenation intended to make compound A formed B instead.
(b) Suggest a mechanism that rationalizes the formation of B.