Textbook Question
Draw the products of the following reactions. If the products can exist as stereoisomers show what stereoisomers are formed.
i. (Z)-2,3-dichloro-2-butene + H2, Pd/C
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Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions
Bruice8th EditionOrganic ChemistryISBN: 9780135213711
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Table of contents
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 1)31
- Ch. 1 - Remembering General Chemistry: Electronic Structure and Bonding (Part 2)65
- Ch. 2 - Acids and Bases: Central to Understanding Organic Chemistry84
- Ch. 3 - An Introduction to Organic Compounds:Nomenclature, Physical Properties, and Structure183
- Ch. 4 - Isomers: The Arrangement of Atoms in Space121
- Ch. 5 - Alkenes: Structure, Nomenclature, and an Introduction to Reactivity • Thermodynamics and Kinetics83
- Ch. 6 - The Reactions of Alkenes • The Stereochemistry of Addition Reactions175
- Ch. 7 - The Reactions of Alkynes • An Introduction to Multistep Synthesis119
- Ch. 8 - Delocalized Electrons: Their Effect on Stability, pKa, and the Products of a Reaction • Aromaticity and Electronic Effects: An Introduction to the Reactions of Benzene148
- Ch. 9 - Substitution and Elimination Reactions of Alkyl Halides212
- Ch. 10 - Reactions of Alcohols, Ethers, Epoxides, Amines, and Sulfur-Containing Compounds131
- Ch. 11 - Organometallic Compounds60
- Ch. 12 - Radicals90
- Ch. 13 - Mass Spectrometry; Infrared Spectroscopy; UV/Vis Spectroscopy62
- Ch. 14 - NMR Spectroscopy95
- Ch. 15 - Reactions of Carboxylic Acids and Carboxylic Acid Derivatives123
- Ch. 16 - Reactions of Aldehydes and Ketones • More Reactions of Carboxylic Acid Derivatives141
- Ch. 17 - Reactions at the Alpha-Carbon101
- Ch. 18 - Reactions of Benzene and Substituted Benzenes144
- Ch. 19 - More About Amines • Reactions of Heterocyclic Compounds49
- Ch. 20 - The Organic Chemistry of Carbohydrates80
- Ch. 21 - Amino Acids, Peptides, and Proteins57
- Ch. 22 - Catalysis in Organic Reactions and in Enzymatic Reactions35
- Ch. 23 - The Organic Chemistry of the Coenzymes—Compounds Derived from Vitamins1
- Ch. 28 - Pericyclic Reactions58
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Bruice 8th EditionCh. 6 - The Reactions of Alkenes • The Stereochemistry of Addition ReactionsProblem 87j
Bruice 8th EditionCh. 6 - The Reactions of Alkenes • The Stereochemistry of Addition ReactionsProblem 87jChapter 7, Problem 87j
Draw the products of the following reactions. If the products can exist as stereoisomers show what stereoisomers are formed.
j. (E)-2,3-dichloro-2-butene + H2, Pd/C
Verified step by step guidance1
Identify the type of reaction: The reaction involves (E)-2,3-dichloro-2-butene reacting with H₂ in the presence of Pd/C. This is a catalytic hydrogenation reaction, which typically reduces double bonds to single bonds by adding hydrogen atoms across the double bond.
Analyze the starting material: (E)-2,3-dichloro-2-butene is an alkene with two chlorine atoms attached to the second and third carbons. The (E)-configuration indicates that the chlorine atoms are on opposite sides of the double bond.
Determine the effect of hydrogenation: The double bond in the alkene will be reduced to a single bond, and two hydrogen atoms will be added to the carbons that were part of the double bond. This will convert the molecule into a saturated compound.
Consider stereochemistry: Since the double bond is being reduced, the resulting product will have free rotation around the single bond. However, the two chlorine atoms on the adjacent carbons can lead to the formation of stereoisomers (diastereomers). Specifically, the product can exist as a pair of stereoisomers: one where the chlorine atoms are on the same side (cis) and one where they are on opposite sides (trans).
Draw the products: Represent the two possible stereoisomers of the product. For the cis isomer, both chlorine atoms will be on the same side of the single bond. For the trans isomer, the chlorine atoms will be on opposite sides. Ensure that the hydrogens added during the reaction are also shown in the structure.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Hydrogenation
Hydrogenation is a chemical reaction that involves the addition of hydrogen (H2) to an unsaturated compound, typically alkenes or alkynes, in the presence of a catalyst such as palladium on carbon (Pd/C). This process converts double or triple bonds into single bonds, resulting in saturated hydrocarbons. In the context of the given reaction, hydrogenation of (E)-2,3-dichloro-2-butene will lead to the formation of a saturated product.
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The definition of hydrogenation.
Stereoisomerism
Stereoisomerism refers to the phenomenon where compounds have the same molecular formula and connectivity of atoms but differ in the spatial arrangement of their atoms. In the case of the hydrogenation of (E)-2,3-dichloro-2-butene, the resulting product can exhibit stereoisomerism due to the presence of chiral centers or restricted rotation around bonds. Identifying and drawing these stereoisomers is crucial for understanding the full scope of the reaction's products.
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Chirality and Chiral Centers
Chirality is a property of a molecule that makes it non-superimposable on its mirror image, often due to the presence of chiral centers—typically carbon atoms bonded to four different substituents. In the context of the reaction, the hydrogenation of (E)-2,3-dichloro-2-butene can create a chiral product if the resulting molecule has two different groups attached to a carbon atom after the addition of hydrogen. Recognizing chiral centers is essential for determining the possible stereoisomers formed in the reaction.
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Related Practice
Textbook Question
Draw the products of the following reactions. If the products can exist as stereoisomers show what stereoisomers are formed.
h. cis-2-butene + HBr
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Textbook Question
Draw the products of the following reactions. If the products can exist as stereoisomers show what stereoisomers are formed.
k. (Z)-3,4-dimethyl-3-hexene + H2, Pd/C
l. (E)-3,4-dimethyl-3-hexene + H2, Pd/C
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Textbook Question
A, a compound with molecular formula C6H10, contains three methylene units. A reacts with one equivalent of H2 over Pd/C to yield B. A reacts with aqueous acid to form a single product, C, and undergoes hydroboration/oxidation to form a pair of enantiomers, D and E. Ozonolysis of A followed by reaction with dimethyl sulfide forms F with molecular formula C6H10O2. Provide structures for A–F.
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Textbook Question
Draw the products of the following reactions. If the products can exist as stereoisomers show what stereoisomers are formed.
g. 3,3-dimethyl-1-pentene + HBr
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Textbook Question
Of the possible products shown for the following reaction, are there any that will not be formed?
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