Textbook Question
p-Nitrophenol (pKa = 7.2) is ten times more acidic than m-nitrophenol (pKa = 8.4) Explain.
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Ch. 21 - Conjugated Systems I: Stability and Addition Reactions
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471
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Table of contents
- Ch. 2 - General Chemistry Translated: Finding the Electrons114
- Ch. 3 - Alkanes and Cycloalkanes: Properties and Conformational Analysis109
- Ch. 4 - Acids and Bases: Electron Flow144
- Ch. 5 - Chemical Reaction Analysis: Thermodynamics and Kinetics118
- Ch. 6 - Stereoisomerism: Arrangement of Atoms in Space112
- Ch. 7 - Principles of Green (Organic) Chemistry3
- Ch. 8 - Alkenes I: Properties and Electrophilic Additions158
- Ch. 9 - Alkenes II: Oxidation and Reduction150
- Ch. 10 - Alkynes: Electrophilic Addition and Redox Reactions101
- Ch. 11 - Properties and Synthesis of Alkyl Halides: Radical Reactions108
- Ch. 12 - Substitution and Elimination: Reactions of Haloalkanes172
- Ch. 13 - Alcohols, Ethers and Related Compounds: Substitution and Elimination239
- Ch. 14 - Structural Identification I: Infrared Spectroscopy and Mass Spectrometry54
- Ch. 15 - Structural Identification II: Nuclear Magnetic Resonance Spectroscopy93
- Ch. 16 - Metals in Organic Chemistry48
- Ch. 17 - Carbonyl Addition Reactions: Aldehydes and Ketones45
- Ch. 18 - Nucleophilic Acyl Substitution I: Carboxylic Acids18
- Ch. 19 - Nucleophilic Acyl Substitution II: Carboxylic Acid Derivatives39
- Ch. 20 - Enolates: Carbonyl Addition and Substitution13
- Ch. 21 - Conjugated Systems I: Stability and Addition Reactions56
- Ch. 22 - Conjugated Systems II: Pericyclic Reactions54
- Ch. 23 - Benzene I: Aromatic Stability and Substitution Reactions64
- Ch. 24 - Benzene II: Reactions Influenced by the Aromatic Ring62
- Ch. 25 - Amines: Structure, Reactions, and Synthesis27
- Ch. 26 - Amino Acids, Proteins, and Peptide Synthesis9
- Ch. 27 - Carbohydrates, Nucleic Acids, and Lipids54
Mullins1st EditionOrganic Chemistry: A Learner Centered ApproachISBN: 9780137566471Not the one you use?Change textbook
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Mullins 1st EditionCh. 21 - Conjugated Systems I: Stability and Addition ReactionsProblem 9
Mullins 1st EditionCh. 21 - Conjugated Systems I: Stability and Addition ReactionsProblem 9Chapter 20, Problem 9
There were actually two possible products in the solvolysis reaction from Figure 21.10. Show both products. Which would you expect to be more stable? Why?
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Identify the solvolysis reaction mechanism: Solvolysis typically involves a nucleophilic substitution reaction (SN1 or SN2) or elimination (E1 or E2). In this case, the reaction likely proceeds via an SN1 mechanism due to the mention of multiple products, which is common in SN1 reactions due to carbocation intermediates.
Determine the intermediate: In an SN1 reaction, the leaving group departs first, forming a carbocation intermediate. Analyze the structure of the starting material to determine the carbocation formed after the leaving group departs.
Consider carbocation rearrangement: Carbocations can rearrange to form a more stable carbocation (e.g., via hydride or alkyl shifts). Check if the initial carbocation can undergo rearrangement to form a more stable carbocation, such as a tertiary carbocation.
Predict the products: Once the carbocation intermediate(s) are identified, consider the nucleophile (solvent) attacking the carbocation. This can lead to two possible products: one from the direct attack on the initial carbocation and another from the attack on the rearranged carbocation.
Evaluate stability: Compare the stability of the two products. Stability is influenced by factors such as hyperconjugation, resonance, and steric hindrance. The more stable product is typically the major product due to thermodynamic control.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Solvolysis Reaction
A solvolysis reaction is a type of nucleophilic substitution where a solvent acts as the nucleophile, typically resulting in the formation of an alcohol or other product. In organic chemistry, this process often involves the breaking of a carbon-leaving group bond and the formation of a new bond with the solvent. Understanding the mechanism of solvolysis, including factors like solvent polarity and nucleophilicity, is crucial for predicting the products formed.
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Heck Reaction
Stability of Reaction Products
The stability of reaction products in organic chemistry is influenced by factors such as steric hindrance, electronic effects, and resonance. More stable products are generally favored in reactions, as they have lower energy and are less reactive. In the context of solvolysis, the stability of the carbocation intermediate formed during the reaction can significantly affect the final products, with more substituted carbocations being more stable due to hyperconjugation and inductive effects.
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Carbocation Stability
Carbocation stability is a key concept in organic chemistry, referring to the relative stability of positively charged carbon species. Carbocations can be classified as primary, secondary, or tertiary based on the number of alkyl groups attached to the positively charged carbon. Tertiary carbocations are the most stable due to greater hyperconjugation and inductive effects from surrounding alkyl groups, which help to disperse the positive charge, making them more favorable intermediates in reactions like solvolysis.
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Related Practice
Textbook Question
Hexa-1,3,5-triene uses six p orbitals, each containing a single electron, to make its three π bonds. How many total molecular orbitals are made by the six p orbitals?
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Textbook Question
Suppose a molecule is formed by the overlap of 16 atomic orbitals.
(a) How many molecular orbitals will be present?
(b) How many will be bonding?
(c) How many will be antibonding?
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Textbook Question
Predict the product and provide a mechanism for the reaction of 1-methylcyclohexene with HBr.
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Textbook Question
To this point, hydrogenation has always been an exothermic process. Using the numbers from Figure 21.6, calculate ∆Hohydr for each step of the reduction of benzene.
∆H1 + ∆H2 + ∆H3 = ∆Htot = ―49.5 kcal /mol (―208 kJ/mol)
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Textbook Question
Hydroboration, an electrophilic addition reaction like those studied in Section 21.4, only gives 1,2-addition to buta-1,3-diene, regardless of temperature. Why?
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