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Ch.20 - Electrochemistry
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Not the one you use?Change textbook
All textbooksBrown 15th EditionCh.20 - ElectrochemistryProblem 102c
Chapter 20, Problem 102c

Gold exists in two common positive oxidation states, +1 and +3. The standard reduction potentials for these oxidation states are Au+1aq2 + e- ¡ Au1s2 Ered ° = +1.69 V Au3+1aq2 + 3 e- ¡ Au1s2 Ered ° = +1.50 V (c) Miners obtain gold by soaking gold-containing ores in an aqueous solution of sodium cyanide. A very soluble complex ion of gold forms in the aqueous solution because of the redox reaction 4 Au1s2 + 8 NaCN1aq2 + 2 H2O1l2 + O21g2 ¡ 4 Na3Au1CN2241aq2 + 4 NaOH1aq2 What is being oxidized, and what is being reduced in this reaction?

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Identify the oxidation states of gold in the reactants and products. In the reactants, gold (Au) is in its elemental form, which has an oxidation state of 0. In the products, gold is part of the complex ion Na3Au(CN)4, where it typically has an oxidation state of +1.
Determine the change in oxidation state for gold. Gold goes from an oxidation state of 0 in the reactants to +1 in the products, indicating that gold is being oxidized.
Identify the other elements involved in the reaction. Oxygen (O2) is present in the reactants and is typically in the 0 oxidation state. In the products, it is part of NaOH, where it has an oxidation state of -2.
Determine the change in oxidation state for oxygen. Oxygen goes from an oxidation state of 0 in O2 to -2 in NaOH, indicating that oxygen is being reduced.
Conclude that in this redox reaction, gold (Au) is being oxidized, and oxygen (O2) is being reduced.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Oxidation and Reduction

Oxidation and reduction are chemical processes that involve the transfer of electrons between species. Oxidation refers to the loss of electrons, resulting in an increase in oxidation state, while reduction involves the gain of electrons, leading to a decrease in oxidation state. In redox reactions, one species is oxidized and another is reduced, which is essential for understanding the overall reaction.
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Standard Reduction Potentials

Standard reduction potentials (E°) are measures of the tendency of a chemical species to be reduced, expressed in volts. A higher E° value indicates a greater likelihood of reduction occurring. In the context of the given question, comparing the E° values of Au+1 and Au3+ helps determine which species is more likely to be reduced during the reaction, guiding the identification of oxidized and reduced components.
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Complex Ion Formation

Complex ions are formed when metal ions coordinate with ligands, which are molecules or ions that can donate electron pairs. In the reaction involving gold and sodium cyanide, the formation of the complex ion Na3Au(CN)2 illustrates how gold ions interact with cyanide ligands. Understanding this concept is crucial for analyzing the overall redox process and the stability of the resulting complex in solution.
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Related Practice
Textbook Question

Predict whether the following reactions will be spontaneous in acidic solution under standard conditions: (a) oxidation of Sn to Sn2+ by I2 (to form I-), (b) reduction of Ni2+ to Ni by I- (to form I2), (c) reduction of Ce4+ to Ce3+ by H2O2, (d) reduction of Cu2+ to Cu by Sn2+ (to form Sn4+).

Textbook Question

A voltaic cell is constructed that uses the following half-cell reactions:

Cu+(aq) + e- → Cu(s)

I2(s) + 2 e- → 2 I-(aq)

The cell is operated at 298 K with [Cu+] = 0.25 M and [I-] = 0.035 M.

(a) Determine E for the cell at these concentrations.

Textbook Question

A disproportionation reaction is an oxidation–reduction reaction in which the same substance is oxidized and reduced. Complete and balance the following disproportionation reactions:

(b) MnO42-(aq) → MnO4-(aq) + MnO2(s) (acidic solution)