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Ch.15 - Chemical Equilibrium
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Not the one you use?Change textbook
All textbooksBrown 15th EditionCh.15 - Chemical EquilibriumProblem 29
Chapter 15, Problem 29

Mercury(I) oxide decomposes into elemental mercury and elemental oxygen: 2 Hg2O(s) ⇌ 4 Hg(l) + O2(g). (a) Write the equilibrium-constant expression for this reaction in terms of partial pressures. (b) Suppose you run this reaction in a solvent that dissolves elemental mercury and elemental oxygen. Rewrite the equilibrium-constant expression in terms of molarities for the reaction, using (solv) to indicate solvation.

Verified step by step guidance
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Step 1: Identify the reaction and the phases of each component. The given reaction is 2 Hg2O(s) ⇌ 4 Hg(l) + O2(g). Note that Hg2O is a solid, Hg is a liquid, and O2 is a gas.
Step 2: Write the equilibrium-constant expression in terms of partial pressures for the gaseous components. Since solids and liquids do not appear in the equilibrium expression, only the gaseous component O2 will be included. The expression is K_p = P_{O2}, where P_{O2} is the partial pressure of O2.
Step 3: Consider the scenario where the reaction occurs in a solvent that dissolves elemental mercury and elemental oxygen. In this case, we need to express the equilibrium constant in terms of molarities.
Step 4: Rewrite the balanced chemical equation considering the solvation: 2 Hg2O(s) ⇌ 4 Hg(solv) + O2(solv). Here, (solv) indicates that the species are dissolved in the solvent.
Step 5: Write the equilibrium-constant expression in terms of molarities for the dissolved species. The expression is K_c = [O2(solv)], where [O2(solv)] is the molarity of dissolved oxygen.

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Equilibrium Constant Expression

The equilibrium constant expression (K) quantifies the ratio of the concentrations or partial pressures of products to reactants at equilibrium. For gaseous reactions, it is expressed in terms of partial pressures, while for reactions in solution, it is expressed in terms of molarities. The general form is K = [products]^[coefficients] / [reactants]^[coefficients], where square brackets denote concentration or pressure.
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Le Chatelier's Principle

Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the system will adjust to counteract the change and restore a new equilibrium. This principle is crucial for understanding how changes in concentration, pressure, or temperature affect the position of equilibrium in a chemical reaction.
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Solvation and Molarity

Solvation refers to the process of surrounding solute particles with solvent molecules, which can affect the concentration of solutes in a solution. Molarity (M) is a measure of concentration defined as moles of solute per liter of solution. In the context of the given reaction, when elemental mercury and oxygen are dissolved, their concentrations must be expressed in molarity, indicating their effective participation in the equilibrium.
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Related Practice
Textbook Question

Consider the equilibrium N2(𝑔) + O2(𝑔) + Br2(𝑔) ⇌ 2 NOBr(𝑔) Calculate the equilibrium constant 𝐾𝑝 for this reaction, given the following information at 298 K:

2 NO(𝑔) + Br2(𝑔) ⇌ 2 NOBr(𝑔) 𝐾𝑐 = 2.02

NO(𝑔) ⇌ N2(𝑔) + O2(𝑔) 𝐾𝑐 = 2.1×1030

Textbook Question

The following equilibria were attained at 823 K:

CoO(s) + H2(g) → Co(s) + H2O(g) Kc = 67

CoO(s) + CO(g) → Co(s) + CO2(g) Kc = 490

Based on these equilibria, calculate the value of 𝐾𝑐 for H2(𝑔)+ CO2(𝑔) ⇌ CO(𝑔) + H2O(𝑔) at 823 K.

Textbook Question

Consider the following equilibrium, for which at 𝐾𝑝 = 0.0752 at 480°C: 2 Cl2(𝑔) + 2 H2O(𝑔) ⇌ 4 HCl(𝑔) + O2(𝑔) (a) What is the value of 𝐾𝑝 for the reaction 4 HCl(𝑔) + O2(𝑔) ⇌ 2 Cl2(𝑔) + 2 H2O(𝑔)?

Textbook Question

The equilibrium 2 NO(𝑔) + Cl2(𝑔) ⇌ 2 NOCl(𝑔) is established at 500.0 K. An equilibrium mixture of the three gases has partial pressures of 0.095 atm, 0.171 atm, and 0.28 atm for NO, Cl2, and NOCl, respectively. (a) Calculate 𝐾𝑝 for this reaction at 500.0 K.