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Ch.13 - Properties of Solutions
Brown - Chemistry: The Central Science 15th Edition
Brown15th EditionChemistry: The Central ScienceISBN: 9780137542970Not the one you use?Change textbook
All textbooksBrown 15th EditionCh.13 - Properties of SolutionsProblem 11
Chapter 13, Problem 11

Suppose you had a balloon made of some highly flexible semipermeable membrane. The balloon is filled completely with a 0.2 M solution of some solute and is submerged in a 0.1 M solution of the same solute:
Initially, the volume of solution in the balloon is 0.25 L. Assuming the volume outside the semipermeable membrane is large, as the illustration shows, what would you expect for the solution volume inside the balloon once the system has come to equilibrium through osmosis? [Section 13.5]

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Identify the process involved: This is an osmosis problem, where solvent molecules move through a semipermeable membrane from a region of lower solute concentration to a region of higher solute concentration.
Determine the initial conditions: The balloon contains a 0.2 M solution, and it is submerged in a 0.1 M solution. The initial volume of the solution inside the balloon is 0.25 L.
Understand the direction of solvent flow: Since the concentration inside the balloon (0.2 M) is higher than outside (0.1 M), solvent will move into the balloon to try to equalize the concentrations.
Predict the change in volume: As solvent enters the balloon, the volume inside the balloon will increase until the osmotic pressure is balanced, and equilibrium is reached.
Conclude the expected outcome: At equilibrium, the concentration difference will be minimized, and the volume inside the balloon will be greater than the initial 0.25 L.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Osmosis

Osmosis is the movement of solvent molecules through a semipermeable membrane from a region of lower solute concentration to a region of higher solute concentration. This process continues until equilibrium is reached, where the concentrations on both sides of the membrane become equal. In this scenario, water will move from the 0.1 M solution outside the balloon into the 0.2 M solution inside, increasing the volume inside the balloon.
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Osmosis Example

Concentration Gradient

A concentration gradient refers to the difference in the concentration of a substance between two areas. In this case, the gradient exists between the 0.2 M solution inside the balloon and the 0.1 M solution outside. The movement of water during osmosis is driven by this gradient, as the system seeks to equalize solute concentrations across the membrane.
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Calculate Concentration of the Basic Form

Equilibrium

Equilibrium in a chemical system occurs when the rates of forward and reverse processes are equal, resulting in no net change in concentration. For osmosis, equilibrium is achieved when the concentrations of solute on both sides of the semipermeable membrane are equal. In this example, the volume of the solution inside the balloon will increase until the solute concentrations inside and outside the balloon are balanced.
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Related Practice
Textbook Question

The diagrams shown represent an emulsion, a true solution, and a liquid crystal. The colored balls represent different liquid molecules. Which diagram corresponds to which type of mixture? [Section 13.6]

Textbook Question

This portion of a phase diagram shows the vapor–pressure curves of a volatile solvent and of a solution of that solvent containing a nonvolatile solute. (b) What are the normal boiling points of the solvent and the solution? [Section 13.5]

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Textbook Question

The figure shows two identical volumetric flasks containing the same solution at two temperatures. (b) Does the molality of the solution change with the change in temperature? [Section 13.4]

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