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Multiple Choice
What is the value of Kp for the reaction 2 SO3(g) ⇌ 2 SO2(g) + O2(g) if the equilibrium partial pressures are P(SO3) = 0.2 atm, P(SO2) = 0.4 atm, and P(O2) = 0.1 atm?
A
0.1
B
0.5
C
2.0
D
1.0
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1
Identify the balanced chemical equation for the reaction: 2 SO3(g) ⇌ 2 SO2(g) + O2(g).
Write the expression for the equilibrium constant Kp for the reaction. Kp is given by the formula: Kp = (P(SO2)^2 * P(O2)) / (P(SO3)^2).
Substitute the given equilibrium partial pressures into the Kp expression: P(SO3) = 0.2 atm, P(SO2) = 0.4 atm, and P(O2) = 0.1 atm.
Calculate the numerator of the Kp expression: (P(SO2)^2 * P(O2)) = (0.4^2 * 0.1).
Calculate the denominator of the Kp expression: (P(SO3)^2) = (0.2^2). Then, divide the result from the numerator by the result from the denominator to find Kp.