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Multiple Choice
Consider the reaction C2H4(g) + H2O(g) -> CH3CH2OH(g). Using the standard thermodynamic data, calculate the equilibrium constant (K) for this reaction at 298.15 K.
A
K = 0.45
B
K = 1.23
C
K = 4.56
D
K = 2.78
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Verified step by step guidance
1
Identify the reaction: C₂H₄(g) + H₂O(g) → CH₃CH₂OH(g). This is a gas-phase reaction involving ethylene, water vapor, and ethanol.
Use the standard Gibbs free energy change (ΔG°) to calculate the equilibrium constant (K) at 298.15 K. The relationship is given by the equation: ΔG° = -RT ln(K), where R is the universal gas constant (8.314 J/mol·K) and T is the temperature in Kelvin.
To find ΔG° for the reaction, use the standard Gibbs free energies of formation (ΔG°f) for each species involved. The equation is: ΔG° = Σ(ΔG°f products) - Σ(ΔG°f reactants).
Substitute the values of ΔG°f for CH₃CH₂OH(g), C₂H₄(g), and H₂O(g) into the equation to calculate ΔG° for the reaction.
Once ΔG° is determined, rearrange the equation ΔG° = -RT ln(K) to solve for K: K = exp(-ΔG° / (RT)). Substitute the values of ΔG°, R, and T to find the equilibrium constant K.