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Multiple Choice
A sample of oxygen gas has a volume of 640 mL at a temperature of 23°C. At what temperature (in °C) will the volume of the oxygen be 820 mL, assuming pressure and amount of gas are constant?
A
60°C
B
35°C
C
70°C
D
50°C
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Verified step by step guidance
1
First, identify the gas law that applies to this problem. Since pressure and the amount of gas are constant, we use Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin. The formula is \( \frac{V_1}{T_1} = \frac{V_2}{T_2} \).
Convert the initial temperature from Celsius to Kelvin. The formula for conversion is \( T(K) = T(°C) + 273.15 \). So, \( T_1 = 23 + 273.15 \).
Set up the equation using Charles's Law: \( \frac{640 \text{ mL}}{T_1} = \frac{820 \text{ mL}}{T_2} \).
Solve for \( T_2 \) in Kelvin by rearranging the equation: \( T_2 = \frac{820 \text{ mL} \times T_1}{640 \text{ mL}} \).
Convert \( T_2 \) from Kelvin back to Celsius using the conversion formula \( T(°C) = T(K) - 273.15 \) to find the final temperature in Celsius.