Multiple Choice
What is the mass (in grams) of 10.00 L of propane vapor (C3H8) at standard temperature and pressure (STP)?
2. Atoms & Elements
Calculating Molar Mass
Multiple Choice
Given that the molar mass of CCl_4 is 153.81 g/mol, how many grams of CCl_4 are required to obtain 5.000 mol?
A
153.81 g
B
30.76 g
C
769.05 g
D
307.62 g
Verified step by step guidance1
Identify the given information: the molar mass of CCl\_4 is 153.81 g/mol, and the amount of substance is 5.000 mol.
Recall the relationship between mass, moles, and molar mass, which is given by the formula: \(\text{mass} = \text{moles} \times \text{molar mass}\).
Substitute the known values into the formula: \(\text{mass} = 5.000 \text{mol} \times 153.81 \text{g/mol}\).
Perform the multiplication to find the mass in grams (do not calculate the final number here, just set up the expression).
Interpret the result as the mass of CCl\_4 required to obtain 5.000 mol.
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