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Multiple Choice
Determine the standard cell potential for the following cell: Ni (s)│Ni2+ (aq) ║Cu2+ (aq)│Cu (s) cell.
A
−0.23 V
B
−0.57 V
C
+0.11 V
D
+0.34 V
E
+0.57 V
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1
Identify the half-reactions for the cell. The given cell is Ni (s) | Ni2+ (aq) || Cu2+ (aq) | Cu (s). The half-reactions are: Ni2+ + 2e- → Ni (s) and Cu2+ + 2e- → Cu (s).
Determine the standard reduction potentials for each half-reaction. From standard tables, the reduction potential for Ni2+ + 2e- → Ni (s) is -0.23 V, and for Cu2+ + 2e- → Cu (s) is +0.34 V.
Identify which half-reaction will act as the anode and which will act as the cathode. The half-reaction with the higher reduction potential will be the cathode. Therefore, Cu2+ + 2e- → Cu (s) is the cathode, and Ni2+ + 2e- → Ni (s) is the anode.
Calculate the standard cell potential (Ecell0) using the formula: Ecell0 = Ecathode0 - Eanode0. Substitute the values: Ecell0 = (+0.34 V) - (-0.23 V).
Simplify the expression to find the standard cell potential. This involves adding the absolute values of the reduction potentials: Ecell0 = 0.34 V + 0.23 V.