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Multiple Choice
In the reaction 2H_2 + O_2 ightarrow 2H_2O, how many moles of hydrogen gas (H_2) are required to react completely with 6.28 mol of oxygen gas (O_2)?
A
6.28 mol
B
2.00 mol
C
3.14 mol
D
12.6 mol
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Verified step by step guidance
1
Identify the balanced chemical equation: \(2H_2 + O_2 \rightarrow 2H_2O\).
From the balanced equation, note the mole ratio between hydrogen gas (\(H_2\)) and oxygen gas (\(O_2\)). It is \(2\) moles of \(H_2\) for every \(1\) mole of \(O_2\).
Given the amount of oxygen gas is \(6.28\) moles, use the mole ratio to find the moles of hydrogen gas required: multiply \(6.28\) moles of \(O_2\) by the ratio \(\frac{2 \text{ moles } H_2}{1 \text{ mole } O_2}\).
Set up the calculation as: \(6.28 \text{ mol } O_2 \times \frac{2 \text{ mol } H_2}{1 \text{ mol } O_2}\).
Perform the multiplication to find the moles of \(H_2\) needed to react completely with \(6.28\) moles of \(O_2\).