Skip to main content
Ch. R - Review of Basic Concepts
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 1, Problem 107

Factor by any method. See Examples 1–7. 64+(3x+2)3

Verified step by step guidance
1
Recognize that the expression is a sum of two terms: \(64\) and \((3x+2)^3\). Notice that \(64\) is a perfect cube since \(64 = 4^3\).
Rewrite the expression as a sum of cubes: \(4^3 + (3x+2)^3\).
Recall the sum of cubes factoring formula: $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$.
Identify \(a = 4\) and \(b = (3x+2)\), then apply the formula: \((4 + (3x+2)) \left(4^2 - 4(3x+2) + (3x+2)^2\right)\).
Simplify the first factor and expand the terms inside the second factor to write the fully factored form.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
4m

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Sum of Cubes Formula

The sum of cubes formula states that a³ + b³ = (a + b)(a² - ab + b²). It is used to factor expressions where two terms are each perfect cubes added together. Recognizing the expression as a sum of cubes allows for straightforward factoring.
Recommended video:
03:41
Special Products - Cube Formulas

Identifying Perfect Cubes

To apply the sum of cubes formula, each term must be a perfect cube. For example, 64 is 4³, and (3x + 2)³ is already a cube. Recognizing these cubes is essential to rewrite the expression in a form suitable for factoring.
Recommended video:
03:41
Special Products - Cube Formulas

Polynomial Factoring Techniques

Factoring polynomials involves rewriting expressions as products of simpler polynomials. Techniques include factoring by grouping, special formulas like sum/difference of cubes, and recognizing patterns. Choosing the correct method simplifies solving or further manipulation.
Recommended video:
07:30
Introduction to Factoring Polynomials