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Ch. 2 - Graphs and Functions
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
All textbooksLial 13th EditionCh. 2 - Graphs and FunctionsProblem 23d
Chapter 3, Problem 23d

For the pair of functions defined, find (f/g)(x).Give the domain of each. See Example 2.
ƒ(x)=√(4x-1), g(x)=1/x

Verified step by step guidance
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First, find the expression for the quotient of the two functions, which is given by \(\left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)}\). Substitute the given functions to get \(\left(\frac{f}{g}\right)(x) = \frac{\sqrt{4x - 1}}{\frac{1}{x}}\).
Simplify the expression by dividing by a fraction, which is equivalent to multiplying by its reciprocal. So, \(\left(\frac{f}{g}\right)(x) = \sqrt{4x - 1} \times x\).
Next, determine the domain of \(f(x) = \sqrt{4x - 1}\). Since the expression inside the square root must be non-negative, set up the inequality \(4x - 1 \geq 0\) and solve for \(x\).
Determine the domain of \(g(x) = \frac{1}{x}\). Since division by zero is undefined, exclude \(x = 0\) from the domain.
Finally, find the domain of \(\left(\frac{f}{g}\right)(x)\) by combining the restrictions from both \(f(x)\) and \(g(x)\). This means the domain includes all \(x\) values that satisfy \(4x - 1 \geq 0\) and \(x \neq 0\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Function Division (f/g)(x)

Dividing two functions f and g means creating a new function (f/g)(x) = f(x) / g(x). This requires evaluating both functions at the same input x and then dividing the results, provided g(x) ≠ 0 to avoid division by zero.
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Multiplying & Dividing Functions

Domain of a Function

The domain of a function is the set of all input values x for which the function is defined. For composite functions like (f/g)(x), the domain is the intersection of the domains of f and g, excluding values that make the denominator zero or cause undefined expressions.
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Domain Restrictions of Composed Functions

Square Root Function Domain Restrictions

For a function involving a square root, such as f(x) = √(4x - 1), the expression inside the root must be non-negative (≥ 0) to produce real outputs. This restriction limits the domain to values of x satisfying 4x - 1 ≥ 0.
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Domain Restrictions of Composed Functions
Related Practice
Textbook Question

For the pair of functions defined, find (ƒ+g)(x). Give the domain of each. See Example 2.

ƒ(x)=√(4x-1), g(x)=1/x

Textbook Question

For the pair of functions defined, find (ƒg)(x). Give the domain of each. See Example 2.

ƒ(x)=√(4x-1), g(x)=1/x

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Textbook Question

For the pair of functions defined, find (ƒ-g)(x).Give the domain of each. See Example 2.

ƒ(x)=√(4x-1), g(x)=1/x

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Textbook Question

Determine whether the three points are the vertices of a right triangle. See Example 3.

(−2,−8),(0,−4),(−4,−7)(-2,-8),(0,-4),(-4,-7)

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Textbook Question

For each graph, determine whether y is a function of x. Give the domain and range of each relation.

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Textbook Question

Graph each piecewise-defined function.

f(x)={2x+1if x≥0xif x<0f(x) =\(\begin{cases}\)2x + 1 & \(\text{if }\) x \(\geq\) 0 \(\x\) & \(\text{if }\) x < 0\(\end{cases}\)

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