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Ch. 1 - Equations and Inequalities
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
All textbooksLial 13th EditionCh. 1 - Equations and InequalitiesProblem 27
Chapter 2, Problem 27

Solve each equation. x/(x-1) - 1/(x+1) = 2/(x2-1)

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Identify the given equation: \(\frac{x}{x-1} - \frac{1}{x+1} = \frac{2}{x^{2} - 1}\).
Recognize that the denominator on the right side, \(x^{2} - 1\), can be factored using the difference of squares: \(x^{2} - 1 = (x-1)(x+1)\).
Find the least common denominator (LCD) for all terms, which is \((x-1)(x+1)\), and multiply every term in the equation by this LCD to eliminate the denominators.
After multiplying, simplify each term by canceling the common factors in the numerators and denominators, resulting in a polynomial equation without fractions.
Solve the resulting polynomial equation for \(x\), and check for any restrictions by ensuring that the values of \(x\) do not make any denominator in the original equation equal to zero.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Rational Expressions and Their Domains

Rational expressions are fractions where the numerator and denominator are polynomials. Understanding their domains is crucial because values that make the denominator zero are excluded. For example, in the equation, x cannot be 1 or -1 since these values make denominators zero, causing undefined expressions.
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Factoring Polynomials

Factoring polynomials involves rewriting expressions as products of simpler polynomials. Recognizing that x² - 1 factors as (x - 1)(x + 1) helps simplify the equation and combine terms effectively. This step is essential for finding a common denominator and solving the equation.
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Solving Rational Equations

Solving rational equations involves finding values of the variable that satisfy the equation without making any denominator zero. This typically requires multiplying both sides by the least common denominator (LCD) to eliminate fractions, simplifying the resulting equation, and checking for extraneous solutions.
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Related Practice
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