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Ch. P - Fundamental Concepts of Algebra
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
All textbooksBlitzer 8th EditionCh. P - Fundamental Concepts of AlgebraProblem 16
Chapter 1, Problem 16

Use the product rule to simplify the expressions in Exercises 13–22. In Exercises 17–22, assume that variables represent nonnegative real numbers. 125x2\(\sqrt{125x^2}\)

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Identify the function as a product of two parts: \(\sqrt{125}\) and \(x^2\).
Rewrite the square root and constants in simpler radical or exponential form: \(\sqrt{125} = \sqrt{25 \times 5} = 5\sqrt{5}\).
Express the entire function as \(5\sqrt{5} \cdot x^2\) to clearly see the product of two functions: \(f(x) = 5\sqrt{5}\) and \(g(x) = x^2\).
Apply the product rule for derivatives, which states: \(\frac{d}{dx}[f(x)g(x)] = f'(x)g(x) + f(x)g'(x)\).
Since \(f(x) = 5\sqrt{5}\) is a constant, its derivative \(f'(x) = 0\). Then find \(g'(x)\) by differentiating \(x^2\) to get \$2x$. Substitute these into the product rule formula to write the derivative expression.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Product Rule for Radicals

The product rule for radicals states that the square root of a product equals the product of the square roots: √(ab) = √a × √b. This rule allows simplification of expressions by separating factors under the radical into simpler parts.
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Simplifying Square Roots

Simplifying square roots involves factoring the radicand into perfect squares and other factors, then taking the square root of perfect squares outside the radical. For example, √125 can be simplified to 5√5 since 125 = 25 × 5.
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Properties of Exponents with Radicals

Variables under radicals can be expressed using fractional exponents, such as √(x^2) = x^(2/2) = x. When variables represent nonnegative real numbers, the square root of x squared simplifies directly to x, ensuring the expression remains valid.
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Related Practice
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The formula C=5/9(F-32) expresses the relationship between Fahrenheit temperature, F, and Celsius temperature, C. In Exercises 17–18, use the formula to convert the given Fahrenheit temperature to its equivalent temperature on the Celsius scale. 50 °F

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In Exercises 1–16, evaluate each algebraic expression for the given value or values of the variable(s). (2x+3y)/(x+1), for x=-2 and y=4

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Multiply or divide as indicated. 6x+93x−15⋅x−54x+6\(\frac{6x + 9}{3x - 15}\) \(\cdot\) \(\frac{x - 5}{4x + 6}\)

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Textbook Question

Evaluate each exponential expression in Exercises 1–22. (33)2(3^3)^2