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Ch. 8 - Sequences, Induction, and Probability
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
Chapter 9, Problem 87

Solve: log2 (x+9) — log2 x = 1.

Verified step by step guidance
1
Recall the logarithmic property that states: \(\log_a b - \log_a c = \log_a \left( \frac{b}{c} \right)\), which allows us to combine the difference of two logs with the same base into a single log of a quotient.
Apply this property to the equation \(\log_2 (x+9) - \log_2 x = 1\) to rewrite it as \(\log_2 \left( \frac{x+9}{x} \right) = 1\).
Rewrite the logarithmic equation in its equivalent exponential form: \(\frac{x+9}{x} = 2^1\).
Simplify the right side to get \(\frac{x+9}{x} = 2\), then multiply both sides by \(x\) to clear the denominator, resulting in \(x + 9 = 2x\).
Solve the linear equation \(x + 9 = 2x\) by isolating \(x\), and then check the solution to ensure it does not make any logarithm argument negative or zero.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Properties of Logarithms

Logarithmic properties, such as the subtraction rule log_b(A) - log_b(B) = log_b(A/B), allow simplification of expressions involving logs. This property is essential for combining or breaking down logarithmic terms to solve equations.
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Change of Base Property

Definition of Logarithms

A logarithm log_b(A) answers the question: to what power must the base b be raised to get A? Understanding this helps convert logarithmic equations into exponential form, which is often easier to solve.
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Logarithms Introduction

Domain Restrictions in Logarithmic Functions

The argument of a logarithm must be positive, so expressions inside logs (like x and x+9) must be greater than zero. Recognizing domain restrictions ensures solutions are valid within the function's domain.
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Domain Restrictions of Composed Functions