Skip to main content
Ch. 7 - Conic Sections
Blitzer - College Algebra 8th Edition
Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook
All textbooksBlitzer 8th EditionCh. 7 - Conic SectionsProblem 37
Chapter 8, Problem 37

Find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x + 1)2 = - 8(y + 1)

Verified step by step guidance
1
Identify the form of the given equation. The equation is \( (x + 1)^2 = -8(y + 1) \), which matches the standard form of a vertical parabola: \( (x - h)^2 = 4p(y - k) \), where \( (h, k) \) is the vertex.
From the equation, determine the vertex \( (h, k) \). Here, \( h = -1 \) and \( k = -1 \), so the vertex is at \( (-1, -1) \).
Find the value of \( p \) by comparing \( 4p \) to the coefficient on the right side. Since \( 4p = -8 \), solve for \( p \) to get \( p = -2 \). The negative value indicates the parabola opens downward.
Use the vertex and \( p \) to find the focus. The focus lies \( p \) units away from the vertex along the axis of symmetry (vertical line \( x = h \)). So, the focus is at \( (h, k + p) = (-1, -1 - 2) \).
Find the directrix, which is a horizontal line \( p \) units in the opposite direction from the vertex. The directrix is \( y = k - p = -1 - (-2) = -1 + 2 \). This line is above the vertex.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
3m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Standard Form of a Parabola

The standard form of a parabola's equation helps identify its orientation and key features. For vertical parabolas, the form is (x - h)^2 = 4p(y - k), where (h, k) is the vertex and p determines the distance to the focus and directrix. Recognizing this form allows you to extract important information directly from the equation.
Recommended video:
5:33
Parabolas as Conic Sections

Vertex, Focus, and Directrix

The vertex is the parabola's turning point, located at (h, k). The focus is a point inside the parabola at a distance p from the vertex, and the directrix is a line perpendicular to the axis of symmetry, also p units from the vertex but in the opposite direction. These elements define the parabola's shape and position.
Recommended video:
08:07
Vertex Form

Graphing Parabolas

Graphing a parabola involves plotting the vertex, focus, and directrix, then sketching the curve that is equidistant from the focus and directrix. Understanding the orientation (upward, downward, left, or right) based on the equation's form is essential for accurate graphing.
Recommended video:
5:28
Horizontal Parabolas
Related Practice
Textbook Question

Find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)2 = 8(y - 1)

Textbook Question

Graph each ellipse and give the location of its foci. (x − 2)²/9 + (y -1)² /4= 1

Textbook Question

In Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)2 = - 4(x - 1)


Textbook Question

Find the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 8x

Textbook Question

Use the center, vertices, and asymptotes to graph each hyperbola. Locate the foci and find the equations of the asymptotes. (x+3)2/25−y2/16=1

Textbook Question

Use the center, vertices, and asymptotes to graph each hyperbola. Locate the foci and find the equations of the asymptotes. (y+2)2/4−(x−1)2/16=1