Find all zeros of the polynomial function or solve the given polynomial equation. Use the Rational Zero Theorem, Descartes's Rule of Signs, and possibly the graph of the polynomial function shown by a graphing utility as an aid in obtaining the first zero or the first root. f(x)=3x4−11x3−x2+19x+6
Ch. 3 - Polynomial and Rational Functions

Chapter 4, Problem 47
In Exercises 47–48, find an nth-degree polynomial function with real coefficients satisfying the given conditions. Verify the real zeros and the given function value. n = 3; 2 and 2 - 3i are zeros; f(1) = -10
Verified step by step guidance1
Identify the given zeros of the polynomial. Since the polynomial has real coefficients and one zero is complex (2 - 3i), its complex conjugate (2 + 3i) must also be a zero. So, the zeros are 2, 2 - 3i, and 2 + 3i.
Write the polynomial in factored form using the zeros: \(f(x) = a(x - 2)(x - (2 - 3i))(x - (2 + 3i))\), where \(a\) is a real number coefficient to be determined.
Simplify the product of the complex conjugate factors: \((x - (2 - 3i))(x - (2 + 3i))\) can be expanded using the difference of squares formula for complex conjugates: \((x - 2)^2 - (3i)^2\).
Calculate the simplified quadratic factor: \((x - 2)^2 - (3i)^2 = (x - 2)^2 - (-9) = (x - 2)^2 + 9\). So the polynomial becomes \(f(x) = a(x - 2)((x - 2)^2 + 9)\).
Use the given function value \(f(1) = -10\) to find \(a\). Substitute \(x = 1\) into the polynomial and solve for \(a\): \(f(1) = a(1 - 2)((1 - 2)^2 + 9) = -10\).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Polynomial Zeros and Their Multiplicity
Zeros of a polynomial are the values of x that make the polynomial equal to zero. For an nth-degree polynomial, there are n zeros (counting multiplicities). Understanding zeros helps in constructing the polynomial by forming factors like (x - zero).
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Finding Zeros & Their Multiplicity
Complex Conjugate Root Theorem
If a polynomial has real coefficients and a complex zero a + bi, then its conjugate a - bi is also a zero. This ensures the polynomial remains with real coefficients. For example, if 2 - 3i is a zero, then 2 + 3i must also be a zero.
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Complex Conjugates
Using Given Function Values to Find Leading Coefficient
After forming the polynomial from its zeros, the leading coefficient can be found by substituting a given x-value and its corresponding function value into the polynomial. This step ensures the polynomial satisfies all given conditions.
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Finding Equations of Lines Given Two Points
Related Practice
Textbook Question
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