Ch. 2 - Functions and Graphs

Blitzer8th EditionCollege AlgebraISBN: 9780136970514Not the one you use?Change textbook

Blitzer 8th Edition

Ch. 2 - Functions and Graphs

Problem 32a

Chapter 3, Problem 32a

Evaluate each function at the given values of the independent variable and simplify. h(x) = x³ − x + 1 a. h (3)

Verified step by step guidance

Step 1: Understand the problem. The function h(x) = x³ − x + 1 is given, and we are tasked with evaluating the function at x = 3. This means substituting x = 3 into the function and simplifying the resulting expression.

Step 2: Substitute x = 3 into the function h(x). This gives h(3) = (3)³ − (3) + 1.

Step 3: Simplify the first term, (3)³. Recall that raising a number to the power of 3 means multiplying the number by itself three times: (3)³ = 3 × 3 × 3.

Step 4: Simplify the remaining terms. After calculating (3)³, subtract 3 and then add 1 to the result.

Step 5: Combine all the simplified terms to find the value of h(3). This will give the final result of the function evaluation.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.

Video duration:

Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Function Evaluation

Function evaluation involves substituting a specific value for the independent variable in a function. In this case, to evaluate h(3), you replace x in the function h(x) = x³ − x + 1 with 3. This process allows you to find the output of the function for that particular input.

Polynomial Functions

The function h(x) = x³ − x + 1 is a polynomial function, which is a mathematical expression consisting of variables raised to whole number powers and coefficients. Understanding polynomial functions is essential as they can exhibit various behaviors, such as growth rates and turning points, depending on their degree and coefficients.

Simplification

Simplification in mathematics refers to the process of reducing an expression to its simplest form. After evaluating the function h(3), you may need to combine like terms or perform arithmetic operations to arrive at a final, simplified result. This step is crucial for clarity and ease of interpretation in mathematical expressions.

Recommended video:

Guided course

04:15

Multiply Polynomials Using the Distributive Property

Related Practice

Textbook Question

Use the graph of y = f(x) to graph each function g. g(x) = 2f(x+2) − 1

views

Textbook Question

Evaluate each function at the given values of the independent variable and simplify. h(x) = x³ − x + 1 b. h (-2)

views

Textbook Question

Use the given conditions to write an equation for each line in point-slope form and slope-intercept form. Passing through (−3, 6) and (3, −2)

Textbook Question

Evaluate each function at the given values of the independent variable and simplify. h(x) = x³ − x + 1 d. h (3a)

Textbook Question

Evaluate each function at the given values of the independent variable and simplify. h(x) = x³ − x + 1 c. h (-x)

Textbook Question

In Exercises 27–38, evaluate each function at the given values of the independent variable and simplify. h(x) = x⁴ - x²+1 d. h (3a)