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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 8, Problem 8.2.76

Use integration by parts to obtain the formula ∫ √(1 - x²) dx = (1/2) x √(1 - x²) + (1/2) ∫ 1 / √(1 - x²) dx.

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Identify the integral to solve: \(\int \sqrt{1 - x^{2}} \, dx\).
Choose parts for integration by parts: let \(u = \sqrt{1 - x^{2}}\) and \(dv = dx\).
Compute \(du\) and \(v\): differentiate \(u\) to get \(du = \frac{d}{dx} \left( (1 - x^{2})^{1/2} \right) dx = \frac{-x}{\sqrt{1 - x^{2}}} dx\), and integrate \(dv\) to get \(v = x\).
Apply the integration by parts formula: \(\int u \, dv = uv - \int v \, du\), so write \(\int \sqrt{1 - x^{2}} \, dx = x \sqrt{1 - x^{2}} - \int x \left( \frac{-x}{\sqrt{1 - x^{2}}} \right) dx\).
Simplify the integral inside: \(- \int x \left( \frac{-x}{\sqrt{1 - x^{2}}} \right) dx = \int \frac{x^{2}}{\sqrt{1 - x^{2}}} dx\). Then express \(x^{2}\) as \(1 - (1 - x^{2})\) to rewrite the integral and separate it into simpler parts, leading to the formula \(\int \sqrt{1 - x^{2}} \, dx = \frac{1}{2} x \sqrt{1 - x^{2}} + \frac{1}{2} \int \frac{1}{\sqrt{1 - x^{2}}} dx\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Integration by Parts

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