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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.1.84

84. Find lim(x→∞) (√(x² + 1) - √x).

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Identify the limit expression: \(\lim_{x \to \infty} \left( \sqrt{x^{2} + 1} - \sqrt{x} \right)\).
Recognize that as \(x\) approaches infinity, both \(\sqrt{x^{2} + 1}\) and \(\sqrt{x}\) grow large, so direct substitution leads to an indeterminate form of type \(\infty - \infty\).
To resolve this, multiply and divide the expression by the conjugate of the difference to rationalize it: multiply by \(\frac{\sqrt{x^{2} + 1} + \sqrt{x}}{\sqrt{x^{2} + 1} + \sqrt{x}}\).
Simplify the numerator using the difference of squares formula: \(\left( \sqrt{x^{2} + 1} - \sqrt{x} \right) \left( \sqrt{x^{2} + 1} + \sqrt{x} \right) = (x^{2} + 1) - x\).
Rewrite the limit as \(\lim_{x \to \infty} \frac{(x^{2} + 1) - x}{\sqrt{x^{2} + 1} + \sqrt{x}}\) and then simplify the numerator and denominator separately to analyze the behavior as \(x\) approaches infinity.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Limits at Infinity

Limits at infinity describe the behavior of a function as the input grows without bound. Understanding how expressions behave as x approaches infinity helps determine if the function approaches a finite value, infinity, or does not exist.
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Rationalizing Expressions

Rationalizing involves multiplying by a conjugate to simplify expressions with square roots. This technique helps eliminate radicals in the numerator or denominator, making it easier to evaluate limits or simplify complex expressions.
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Asymptotic Behavior of Square Root Functions

For large x, √(x² + 1) behaves like |x| because the x² term dominates. Recognizing this helps approximate and simplify expressions involving square roots when x approaches infinity, aiding in limit evaluation.
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