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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.8.2e

2. Which of the following functions grow faster than e^x as x→∞? Which grow at the same rate as e^x? Which grow slower?
e. e^(-x)

Verified step by step guidance
1
Recall that the function \(e^x\) grows exponentially as \(x \to \infty\), meaning it increases very rapidly without bound.
Consider the given function \(e^{-x}\). Rewrite it as \(\frac{1}{e^x}\) to better understand its behavior as \(x \to \infty\).
As \(x \to \infty\), \(e^x\) becomes very large, so \(\frac{1}{e^x}\) approaches 0. This means \(e^{-x}\) approaches 0 and does not grow; it actually decays to zero.
Compare the growth rates: since \(e^{-x}\) approaches zero while \(e^x\) grows without bound, \(e^{-x}\) grows slower than \(e^x\) as \(x \to \infty\).
Therefore, \(e^{-x}\) grows slower than \(e^x\) as \(x\) approaches infinity.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Exponential Growth and Decay

Exponential functions like e^x grow rapidly as x approaches infinity, while functions like e^(-x) decay towards zero. Understanding the difference between growth and decay is essential to compare their rates as x→∞.
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Limits and Asymptotic Behavior

Analyzing the limit of a function as x approaches infinity helps determine its growth rate relative to others. Functions that approach infinity faster have higher growth rates, while those approaching zero or finite values grow slower.
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Comparing Growth Rates of Functions

Functions can be compared by examining their dominant terms as x→∞. For example, polynomial, exponential, and logarithmic functions grow at different rates, with exponential functions like e^x generally outpacing polynomials and logarithms.
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