Skip to main content
Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.4b

Finding Antiderivatives
In Exercises 1–16, find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation.
x⁻³/2 + x²

Verified step by step guidance
1
Identify the function to find the antiderivative of: \(f(x) = x^{-\frac{3}{2}} + x^{2}\).
Recall the power rule for antiderivatives: for \(f(x) = x^{n}\), an antiderivative is \(F(x) = \frac{x^{n+1}}{n+1} + C\), provided \(n \neq -1\).
Apply the power rule to each term separately: for \(x^{-\frac{3}{2}}\), add 1 to the exponent to get \(-\frac{3}{2} + 1 = -\frac{1}{2}\), so the antiderivative is \(\frac{x^{-\frac{1}{2}}}{-\frac{1}{2}}\).
For the second term \(x^{2}\), add 1 to the exponent to get \(2 + 1 = 3\), so the antiderivative is \(\frac{x^{3}}{3}\).
Combine the antiderivatives of both terms and add the constant of integration \(C\): \(F(x) = \frac{x^{-\frac{1}{2}}}{-\frac{1}{2}} + \frac{x^{3}}{3} + C\).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
4m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Antiderivative (Indefinite Integral)

An antiderivative of a function is another function whose derivative equals the original function. It represents the reverse process of differentiation and is expressed with an arbitrary constant since differentiation of a constant is zero.
Recommended video:
05:04
Introduction to Indefinite Integrals

Power Rule for Integration

The power rule states that the antiderivative of x^n (where n ≠ -1) is (x^(n+1)) / (n+1) plus a constant. This rule is fundamental for integrating polynomial terms and applies directly to terms like x^2 and x^(-3/2).
Recommended video:
04:04
Power Rule for Indefinite Integrals

Verification by Differentiation

After finding an antiderivative, differentiating it should return the original function. This step confirms the correctness of the antiderivative and helps identify any mistakes in the integration process.
Recommended video:
05:53
Finding Differentials