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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.5a

Finding Antiderivatives
In Exercises 1–16, find an antiderivative for each function. Do as many as you can mentally. Check your answers by differentiation.
1 / x²

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1
Recognize that the function given is \(\frac{1}{x^2}\), which can be rewritten as \(x^{-2}\) to make it easier to apply the power rule for antiderivatives.
Recall the power rule for antiderivatives: for any function \(x^n\) where \(n \neq -1\), the antiderivative is \(\frac{x^{n+1}}{n+1} + C\), where \(C\) is the constant of integration.
Apply the power rule to \(x^{-2}\) by increasing the exponent by 1: \(-2 + 1 = -1\), so the antiderivative will be \(\frac{x^{-1}}{-1} + C\).
Simplify the expression to get the antiderivative in a more standard form: \(-x^{-1} + C\), which can also be written as \(-\frac{1}{x} + C\).
Verify your answer by differentiating \(-\frac{1}{x} + C\) and checking that the derivative is \(\frac{1}{x^2}\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Antiderivatives (Indefinite Integrals)

An antiderivative of a function is another function whose derivative equals the original function. It represents the reverse process of differentiation and is expressed as an indefinite integral with a constant of integration, C, since differentiation loses constant terms.
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Power Rule for Integration

The power rule for integration states that for any real number n ≠ -1, the integral of x^n dx is (x^(n+1)) / (n+1) + C. This rule is essential for finding antiderivatives of polynomial and power functions like 1/x², which can be rewritten as x^(-2).
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Verification by Differentiation

After finding an antiderivative, differentiating it should return the original function. This step confirms the correctness of the antiderivative and helps identify any mistakes in the integration process.
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