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Ch. 2 - Limits and Continuity
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 2, Problem 2.6.61a

Find the limits in Exercises 59–62. Write ∞ or −∞ where appropriate.


lim ( 1 / x²/³ + 2 / (x − 1)²/³ ) as


a. x → 0⁺

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1
Step 1: Understand the problem. We need to find the limit of the expression \( \frac{1}{x^{2/3}} + \frac{2}{(x - 1)^{2/3}} \) as \( x \to 0^+ \). This means we are approaching 0 from the positive side.
Step 2: Analyze the behavior of each term separately as \( x \to 0^+ \). For the term \( \frac{1}{x^{2/3}} \), as \( x \) approaches 0 from the positive side, \( x^{2/3} \) approaches 0, making \( \frac{1}{x^{2/3}} \) approach infinity.
Step 3: Consider the second term \( \frac{2}{(x - 1)^{2/3}} \). As \( x \to 0^+ \), \( x - 1 \) approaches -1. Therefore, \( (x - 1)^{2/3} \) approaches \((-1)^{2/3}\), which is a real number. Thus, \( \frac{2}{(x - 1)^{2/3}} \) approaches a finite value.
Step 4: Combine the behavior of both terms. The first term \( \frac{1}{x^{2/3}} \) dominates the behavior of the limit because it approaches infinity, while the second term approaches a finite value.
Step 5: Conclude the limit. Since the first term approaches infinity and dominates the expression, the limit of the entire expression as \( x \to 0^+ \) is infinity.

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