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Ch. 10 - Infinite Sequences and Series
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 10, Problem 10.7.36a

Intervals of Convergence
In Exercises 1–36, (a) find the series’ radius and interval of convergence.
∑ (from n = 1 to ∞) [ (√(n + 1) − √n)(x − 3)ⁿ ]

Verified step by step guidance
1
Identify the general term of the series: \[a_n = (\sqrt{n+1} - \sqrt{n})(x - 3)^n\].
To find the radius of convergence, consider the absolute value of the terms without the \((x-3)^n\) part, and apply the Root Test or Ratio Test. Here, the Ratio Test is more straightforward.
Compute the limit $\(L = \(\lim\)_{n \(\to\) \(\infty\)} \(\left\)| \(\frac{a_{n+1}\)}{a_n} \(\right\)| = \(\lim\)_{n \(\to\) \(\infty\)} \(\left\)| \(\frac{(\sqrt{n+2}\) - \(\sqrt{n+1}\))(x - 3)^{n+1}}{(\(\sqrt{n+1}\) - \(\sqrt{n}\))(x - 3)^n} \(\right\)| = \(\lim\)_{n \(\to\) \(\infty\)} \(\left\)| \(\frac{\sqrt{n+2}\) - \(\sqrt{n+1}\)}{\(\sqrt{n+1}\) - \(\sqrt{n}\)} \(\right\)| \(\cdot\) |x - 3|.\)
Simplify the ratio of the square root differences by rationalizing or using the conjugate to find the limit of \[\frac{\sqrt{n+2} - \sqrt{n+1}}{\sqrt{n+1} - \sqrt{n}}\] as \[n \to \infty\].
Set the limit \[L < 1\] to find the radius of convergence, then solve the inequality \[|x - 3| < R\] where \[R\] is the radius. Finally, check the endpoints \[x = 3 - R\] and \[x = 3 + R\] by substituting back into the original series to determine if the series converges or diverges at those points, thus finding the interval of convergence.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Radius of Convergence

The radius of convergence is the distance from the center of a power series within which the series converges absolutely. It can be found using tests like the Ratio Test or Root Test applied to the general term of the series. This radius determines the interval on the x-axis where the series behaves well.
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Interval of Convergence

The interval of convergence is the set of all x-values for which the power series converges. It is centered at the series’ center (here, x = 3) and extends to the radius of convergence on both sides. Endpoints must be checked separately to determine if the series converges or diverges there.
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Behavior of the General Term (√(n+1) − √n)

The term (√(n+1) − √n) simplifies to a form involving 1/(√(n+1) + √n), which behaves like 1/(2√n) for large n. Understanding this helps analyze the series’ terms and apply convergence tests correctly, especially since it affects the growth rate of coefficients in the power series.
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