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Ch. 9 - Differential Equations
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 9, Problem 9.2.46c

46–48. Analyzing models The following models were discussed in Section 9.1 and reappear in later sections of this chapter. In each case, carry out the indicated analysis using direction fields.


Drug infusion The delivery of a drug (such as an antibiotic) through an intravenous line may be modeled by the differential equation m′(t)+km(t)=I, where m(t) is the mass of the drug in the blood at time t≥0, K is a constant that describes the rate at which the drug is absorbed, and I is the infusion rate. Let I=10mg/hr and k=0.05 hr^−1.
c. What is the equilibrium solution?

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Identify the given differential equation: \(m'(t) + k m(t) = I\), where \(m(t)\) is the mass of the drug at time \(t\), \(k = 0.05\) hr\(^{-1}\), and \(I = 10\) mg/hr.
Recall that the equilibrium solution occurs when the mass of the drug does not change over time, meaning the derivative \(m'(t) = 0\).
Set \(m'(t) = 0\) in the differential equation to find the equilibrium: \(0 + k m = I\).
Solve for \(m\) to find the equilibrium mass: \(k m = I \implies m = \frac{I}{k}\).
Substitute the given values of \(I\) and \(k\) into the expression to write the equilibrium solution explicitly as \(m = \frac{10}{0.05}\) mg.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Differential Equations and Their Solutions

A differential equation relates a function with its derivatives, describing how the function changes over time. Solving it involves finding a function that satisfies this relationship, often representing real-world processes like drug concentration in the bloodstream.
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Solutions to Basic Differential Equations

Equilibrium Solution of a Differential Equation

An equilibrium solution is a constant solution where the derivative is zero, meaning the system is in a steady state. For the equation m'(t) + km(t) = I, the equilibrium occurs when the rate of change m'(t) = 0, balancing drug infusion and absorption.
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Solutions to Basic Differential Equations

Direction Fields (Slope Fields)

Direction fields graphically represent the slopes of solutions to a differential equation at various points. They help visualize the behavior of solutions over time and identify equilibrium solutions by showing where slopes are zero or constant.
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Understanding Slope Fields
Related Practice
Textbook Question

38–43. Equilibrium solutions A differential equation of the form y′(t)=f(y) is said to be autonomous (the function f depends only on y). The constant function y=y0 is an equilibrium solution of the equation provided f(y0)=0 (because then y'(t)=0 and the solution remains constant for all t). Note that equilibrium solutions correspond to horizontal lines in the direction field. Note also that for autonomous equations, the direction field is independent of t. Carry out the following analysis on the given equations.

c. Sketch the solution curve that corresponds to the initial condition y0=1. 


y′(t) = 2y + 4

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Textbook Question

33–36. {Use of Tech} Computing Euler approximations Use a calculator or computer program to carry out the following steps.

c. Repeating parts (a) and (b) using half the time step used in those calculations, again find an approximation to y(T).


y′(t) = 6 - 2y, y(0) = -1; Δt = 0.2, T = 3; y(t) = 3 - 4e⁻²ᵗ

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Textbook Question

{Use of Tech} Logistic equation for an epidemic When an infected person is introduced into a closed and otherwise healthy community, the number of people who contract the disease (in the absence of any intervention) may be modeled by the logistic equation

 dP/dt=kP(1−P/A),P0=P_0, 

where K is a positive infection rate, A is the number of people in the community, and P0 is the number of infected people at t=0. The model also assumes no recovery. 


c. For a fixed value of K and A, describe the long-term behavior of the solutions, for any P0 with 0<P0<A. 

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Textbook Question

{Use of Tech} Free fall Using th e background given in Exercise 47, assume the resistance is given by f(v)=−Rv, for t≥0, where R>0 is a drag coefficient (an assumption often made for a heavy medium such as water or oil).


c. Find the solution of this separable equation assuming v(0)=0 and 0<v<g/b.

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Textbook Question

29–32. {Use of Tech} Errors in Euler’s method Consider the following initial value problems.


c. Which time step results in the more accurate approximation? Explain your observations.


y′(t) = 4−y, y(0) = 3; y(t) = 4−e⁻ᵗ

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Textbook Question

52-56. In this section, several models are presented and the solution of the associated differential equation is given. Later in the chapter, we present methods for solving these differential equations.


(Use of Tech) Chemical rate equations The reaction of certain chemical compounds can be modeled using a differential equation of the form y'(t) = -kyⁿ(t), where y(t) is the concentration of the compound, for t ≥ 0, k > 0 is a constant that determines the speed of the reaction, and n is a positive integer called the order of the reaction. Assume the initial concentration of the compound is y(0) = y₀ > 0.


c. Let y₀ = 1 and k = 0.1. Graph the first-order and second-order solutions found in parts (a) and (b). Compare the two reactions.