Textbook Question
7-56. Trigonometric substitutions Evaluate the following integrals using trigonometric substitution.
19. ∫ 1/√(x² - 81) dx, x > 9
Ch. 8 - Integration Techniques
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243
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Table of contents
- Ch. 1 - Functions210
- Ch. 2 - Limits371
- Ch. 3 - Derivatives633
- Ch. 4 - Applications of the Derivative412
- Ch. 5 - Integration328
- Ch. 6 - Applications of Integration331
- Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions177
- Ch. 8 - Integration Techniques394
- Ch. 9 - Differential Equations179
- Ch. 10 - Sequences and Infinite Series339
- Ch. 11 - Power Series218
- Ch.12 - Parametric and Polar Curves215
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 8, Problem 8.4.42
7-56. Trigonometric substitutions Evaluate the following integrals using trigonometric substitution.
42. ∫ 1/(x²√(9x² - 1)) dx, x > 1/3
Verified step by step guidance1
Step 1: Recognize that the integral involves a square root of a quadratic expression, √(9x² - 1). This suggests using a trigonometric substitution to simplify the square root. Specifically, let x = (1/3)sec(θ), which transforms the quadratic expression into a form involving sec²(θ).
Step 2: Substitute x = (1/3)sec(θ) into the integral. Compute dx by differentiating x = (1/3)sec(θ), which gives dx = (1/3)sec(θ)tan(θ)dθ. Replace x and dx in the integral.
Step 3: Simplify the square root √(9x² - 1) using the substitution x = (1/3)sec(θ). Substituting x² = (1/9)sec²(θ) into 9x² - 1 gives √(9x² - 1) = √(sec²(θ) - 1) = tan(θ). Replace √(9x² - 1) with tan(θ) in the integral.
Step 4: After substitution, the integral becomes ∫(1/(x²√(9x² - 1)))dx = ∫(1/((1/9)sec²(θ) * tan(θ))) * (1/3)sec(θ)tan(θ)dθ. Simplify the expression by canceling terms and combining factors.
Step 5: The integral simplifies to ∫cos²(θ)dθ after substitution and simplification. Use a trigonometric identity, such as cos²(θ) = (1 + cos(2θ))/2, to rewrite the integral in a solvable form. Proceed to integrate and back-substitute θ using the original substitution x = (1/3)sec(θ).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Trigonometric Substitution
Trigonometric substitution is a technique used in calculus to simplify integrals involving square roots of quadratic expressions. By substituting a variable with a trigonometric function, such as sine or tangent, the integral can often be transformed into a more manageable form. This method is particularly useful for integrals that contain expressions like √(a² - x²), √(x² - a²), or √(x² + a²).
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Integration Techniques
Integration techniques encompass various methods used to evaluate integrals, including substitution, integration by parts, and partial fractions. Understanding these techniques is essential for solving complex integrals, as they provide strategies to break down the integral into simpler parts. Mastery of these methods allows for greater flexibility and efficiency in solving a wide range of integral problems.
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Definite vs. Indefinite Integrals
Definite integrals calculate the area under a curve between two specified limits, while indefinite integrals represent a family of functions without specific bounds. In the context of trigonometric substitution, recognizing whether an integral is definite or indefinite influences the approach taken, particularly in applying limits after substitution. This distinction is crucial for correctly interpreting the results of the integration process.
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Related Practice
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