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Ch. 7 - Logarithmic, Exponential Functions, and Hyperbolic Functions
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 7, Problem 7.R.13

10–19. Derivatives Find the derivatives of the following functions.


f(t) = cosh t sinh t

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1
Recall the product rule for derivatives: if you have a function \(f(t) = u(t) v(t)\), then its derivative is \(f'(t) = u'(t) v(t) + u(t) v'(t)\).
Identify the two functions in the product: \(u(t) = \cosh t\) and \(v(t) = \sinh t\).
Find the derivatives of each function separately: \(\frac{d}{dt} \cosh t = \sinh t\) and \(\frac{d}{dt} \sinh t = \cosh t\).
Apply the product rule: \(f'(t) = (\sinh t)(\sinh t) + (\cosh t)(\cosh t)\).
Simplify the expression if possible, using hyperbolic identities such as \(\cosh^2 t - \sinh^2 t = 1\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hyperbolic Functions

Hyperbolic functions, such as sinh(t) and cosh(t), are analogs of trigonometric functions but based on hyperbolas. They have unique properties and identities, like cosh²(t) - sinh²(t) = 1, which are useful in differentiation and integration.
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Product Rule for Differentiation

The product rule states that the derivative of a product of two functions u(t) and v(t) is u'(t)v(t) + u(t)v'(t). This rule is essential when differentiating functions like f(t) = cosh(t) * sinh(t), where both factors depend on t.
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The Product Rule

Derivatives of Hyperbolic Functions

The derivatives of basic hyperbolic functions are: d/dt[sinh(t)] = cosh(t) and d/dt[cosh(t)] = sinh(t). Knowing these derivatives allows you to apply the product rule correctly to find the derivative of functions involving hyperbolic terms.
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