Determine the area of the shaded region in the following figures.
Ch. 6 - Applications of Integration
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 6, Problem 6.6.17
Find the area of the surface generated when the given curve is revolved about the given axis.
y=1/4(e^2x+e^−2x), for −2≤x≤2; about the x-axis
Verified step by step guidance1
Step 1: Recall the formula for the surface area of a curve revolved about the x-axis. The formula is: , where y is the function being revolved, and dy/dx is its derivative.
Step 2: Compute the derivative of the given function y = (1/4)(e^(2x) + e^(-2x)). Use the chain rule to find dy/dx. The derivative is: .
Step 3: Simplify the expression for dy/dx. Factor out constants where possible: .
Step 4: Substitute y and dy/dx into the surface area formula. The integral becomes: .
Step 5: Simplify the integrand as much as possible and set up the integral for evaluation. You may need to use algebraic manipulation and trigonometric identities to simplify further before solving the integral.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Surface Area of Revolution
The surface area of a solid of revolution is calculated using the formula A = 2π ∫[a to b] y(x) √(1 + (dy/dx)²) dx, where y(x) is the function being revolved, and dy/dx is its derivative. This formula accounts for the curve's shape and the distance from the axis of rotation, allowing us to find the total surface area generated by revolving the curve around the specified axis.
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Parametric Derivatives
To find the derivative dy/dx for the function y = 1/4(e^(2x) + e^(-2x)), we apply differentiation rules. The derivative is essential for the surface area formula, as it represents the slope of the curve at any point, which affects the surface area when the curve is revolved around an axis.
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Definite Integrals
Definite integrals are used to calculate the area under a curve between two points, in this case, from x = -2 to x = 2. The integral provides the accumulated value of the function over the specified interval, which is crucial for determining the total surface area generated by the revolution of the curve.
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Related Practice
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Textbook Question
Find the area of the surface generated when the given curve is revolved about the given axis.
y=√1−x^2, for −1/2≤x≤1/2; about the x-axis
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Textbook Question
Determine the area of the shaded region in the following figures.
Textbook Question
64–68. Shell method Use the shell method to find the volume of the following solids.
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