Ch. 5 - Integration

Briggs - Calculus: Early Transcendentals 3rd Edition

Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook

Briggs 3rd Edition

Ch. 5 - Integration

Problem 5.R.13

Chapter 5, Problem 5.R.13

Limit definition of the definite integral Use the limit definition of the definite integral with right Riemann sums and a regular partition to evaluate the following definite integrals. Use the Fundamental Theorem of Calculus to check your answer.

∫₀⁴ (𝓍³―𝓍) d𝓍

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Step 1: Recall the limit definition of the definite integral. The definite integral ∫ₐᵇ f(𝓍) d𝓍 can be approximated using right Riemann sums with a regular partition. Divide the interval [a, b] into n subintervals of equal width Δ𝓍 = (b - a)/n.

Step 2: For the given integral ∫₀⁴ (𝓍³ - 𝓍) d𝓍, the interval [0, 4] is divided into n subintervals. The width of each subinterval is Δ𝓍 = (4 - 0)/n = 4/n.

Step 3: The right endpoints of the subintervals are given by 𝓍ᵢ = a + iΔ𝓍 = 0 + i(4/n) = (4i)/n, where i ranges from 1 to n.

Step 4: Substitute the function f(𝓍) = 𝓍³ - 𝓍 into the Riemann sum formula. The sum becomes Sₙ = Σᵢ₌₁ⁿ f(𝓍ᵢ)Δ𝓍 = Σᵢ₌₁ⁿ [(𝓍ᵢ³ - 𝓍ᵢ) * Δ𝓍]. Replace 𝓍ᵢ with (4i)/n and Δ𝓍 with 4/n.

Step 5: Simplify the expression for Sₙ: Sₙ = Σᵢ₌₁ⁿ [((4i)/n)³ - (4i)/n] * (4/n). Expand and simplify the terms inside the summation. Then, take the limit as n → ∞ to compute the exact value of the integral. Finally, use the Fundamental Theorem of Calculus to verify the result by directly evaluating ∫₀⁴ (𝓍³ - 𝓍) d𝓍.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Definite Integral

A definite integral represents the signed area under a curve defined by a function over a specific interval. It is calculated as the limit of Riemann sums, which approximate the area by dividing the interval into smaller subintervals and summing the areas of rectangles formed. The notation ∫ₐᵇ f(x) dx indicates the integral of f(x) from a to b.

Riemann Sums

Riemann sums are a method for approximating the value of a definite integral by dividing the area under a curve into rectangles. The height of each rectangle is determined by the function's value at specific points within each subinterval, such as the right endpoint, left endpoint, or midpoint. As the number of rectangles increases (and their width decreases), the Riemann sum approaches the exact value of the definite integral.

Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus links differentiation and integration, stating that if F is an antiderivative of f on an interval [a, b], then the definite integral of f from a to b can be computed as F(b) - F(a). This theorem provides a powerful way to evaluate definite integrals by finding an antiderivative rather than relying solely on Riemann sums.

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(a) Evaluate H (0) .

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∫₀¹ 𝓍ⁿd𝓍 + ∫₀¹ ⁿ√(𝓍d𝓍) = 1

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Textbook Question

Properties of integrals Suppose ∫₁⁴ ƒ(𝓍) d𝓍 = 6 , ∫₁⁴ g(𝓍) d𝓍 = 4 and ∫₃⁴ ƒ(𝓍) d𝓍 = 2 . Evaluate the following integrals or state that there is not enough information.

∫₁³ ƒ(𝓍)/g(𝓍) d𝓍

Limit definition of the definite integral Use the limit definition of the definite integral with right Riemann sums and a regular partition to evaluate the following definite integrals. Use the Fundamental Theorem of Calculus to check your answer. ∫₀⁴ (𝓍³―𝓍) d𝓍

Verified video answer for a similar problem:

Key Concepts

Definite Integral

Riemann Sums

Fundamental Theorem of Calculus

Limit definition of the definite integral Use the limit definition of the definite integral with right Riemann sums and a regular partition to evaluate the following definite integrals. Use the Fundamental Theorem of Calculus to check your answer.

∫₀⁴ (𝓍³―𝓍) d𝓍