Skip to main content
Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
All textbooksBriggs 3rd EditionCh. 3 - DerivativesProblem 3.7.105b
Chapter 3, Problem 3.7.105b

{Use of Tech} Power and energy The total energy in megawatt-hr (MWh) used by a town is given by E(t) = 400t+2400/π sin πt/12, where t≥0 is measured in hours, with t=0 corresponding to noon.
b. At what time of day is the rate of energy consumption a maximum? What is the power at that time of day?

Verified step by step guidance
1
Step 1: To find the time of day when the rate of energy consumption is a maximum, we need to find the derivative of the energy function E(t) with respect to time t. This derivative, E'(t), represents the rate of energy consumption, also known as power.
Step 2: Differentiate E(t) = 400t + \(\frac{2400}{\pi}\) \(\sin\[\left\)(\(\frac{\pi t}{12}\]\right\)) with respect to t. Use the derivative rules: the derivative of 400t is 400, and for the sine term, use the chain rule. The derivative of \(\sin\[\left\)(\(\frac{\pi t}{12}\]\right\)) is \(\cos\[\left\)(\(\frac{\pi t}{12}\]\right\)) \(\cdot\) \(\frac{\pi}{12}\).
Step 3: Set the derivative E'(t) equal to zero to find the critical points. This will help us determine when the rate of energy consumption is at a maximum or minimum. Solve the equation 400 + \(\frac{2400}{\pi}\) \(\cdot\) \(\cos\[\left\)(\(\frac{\pi t}{12}\]\right\)) \(\cdot\) \(\frac{\pi}{12}\) = 0 for t.
Step 4: Solve the equation from Step 3 for t to find the critical points. This involves isolating the cosine term and using inverse trigonometric functions to find the values of t that satisfy the equation.
Step 5: Evaluate the second derivative, E''(t), to determine the concavity at the critical points found in Step 4. If E''(t) is negative at a critical point, it indicates a local maximum. Use this information to identify the time of day when the rate of energy consumption is a maximum.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
8m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Energy Function

The energy function E(t) represents the total energy consumed over time, where E(t) = 400t + (2400/π) sin(πt/12). Understanding this function is crucial as it describes how energy consumption varies with time, allowing us to analyze its behavior and derive important characteristics such as maximum consumption.
Recommended video:
06:21
Properties of Functions

Rate of Change

The rate of energy consumption is determined by the derivative of the energy function, E'(t). This derivative indicates how quickly energy is being consumed at any given time, and finding its maximum value will help identify when the energy consumption is at its peak.
Recommended video:
04:16
Intro To Related Rates

Critical Points

Critical points occur where the derivative E'(t) is zero or undefined. These points are essential for determining local maxima or minima in the energy consumption function. By analyzing these points, we can find the specific time of day when the rate of energy consumption reaches its maximum.
Recommended video:
04:50
Critical Points
Related Practice
Textbook Question

60–62. {Use of Tech} Multiple tangent lines Complete the following steps. <IMAGE>

b. Graph the tangent lines on the given graph.

x+y³−y=1; x=1

Textbook Question

13-26 Implicit differentiation Carry out the following steps.

b. Find the slope of the curve at the given point.

tan xy = x+y; (0,0)

Textbook Question

13-26 Implicit differentiation Carry out the following steps.

b. Find the slope of the curve at the given point.

³√x+³√y⁴ = 2;(1,1)

Textbook Question

For what values of x does g(x) = x−sin x have a slope of 1?

Textbook Question

21–30. Derivatives

b. Evaluate f'(a) for the given values of a.

f(t) = 1/√t; a=9, 1/4

1
views
Textbook Question

Derivatives and tangent lines

b. Determine an equation of the line tangent to the graph of f at the point (a,f(a)) for the given value of a.

f(x) = 1/3x-1; a= 2